带有多个键的元组和df值的python字典

Question

在id下面的我的DataFrame名为df2

ID，'AI'，'DB'，'ML'，'Python'，'IR'

0,1,1,0,0,0

1,1,1,1,0,1

2,1,1,0,1,1

3,1,0,1,0,1

我想创建一个字典，使第一行和索引成为元组，并且值成为字典的值，例如

{

 (0,"AI"):1,(0,"DB"):1,(0,"ML"):0,(0,"Python"):0,(0,"IR"):0,
 (1,"AI"):1,(1,"DB"):1,(1,"ML"):1,(1,"Python"):0,(1,"IR"):0,
 (2,"AI"):1,(2,"DB"):1,(2,"ML"):1,(2,"Python"):0,(2,"IR"):1,
 (3,"AI"):1,(3,"DB"):0,(3,"ML"):1,(3,"Python"):0,(3,"IR"):1,
}

到目前为止，我的试用版your_dict = dict（zip（es，df2））print（your_dict）但是，没有产生我想要的输出

Answer 1

创建索引/列的每种组合，然后使用键作为这些值的元组创建字典，该值是该位置数据框中的值。

import itertools
{(x,y):df[y][x] for x, y in itertools.product(df.index, df.columns)}