[英]Every time selecting present and last row data
我有一个这样的数据框:df =
A B
2019-01-25 08:15:00 368.937200 400.459991
2019-01-25 08:30:00 2446.807365 402.070007
2019-01-25 08:45:00 2928.375786 387.779999
2019-01-25 09:00:00 3336.868420 381.529999
2019-01-25 09:15:00 3735.226080 387.850006
2019-01-25 09:30:00 4087.979328 374.839996
2019-01-25 09:45:00 4398.969370 389.359985
2019-01-25 10:00:00 4636.137977 380.589996
2019-01-25 10:15:00 4933.081631 370.429993
2019-01-25 10:30:00 5181.009806 363.619995
2019-01-25 10:45:00 5356.632156 362.459991
2019-01-25 11:00:00 5528.142683 386.869995
2019-01-25 11:15:00 5668.815429 363.470001
2019-01-25 11:30:00 5795.115442 355.839996
2019-01-25 11:45:00 5823.423663 373.55999
.
.
我想创建一个新列C = A_pre-A_las / B_pre-B_las
A_pre =当前样本A_las =最后样本
例如,
C的数据在08:30 = A(8:30)-A(8:15)/ B(8:30)-B(8:15)
C:08:30的数据=(2446.80-368.93)/(402.07-400.45)= 1282.63
怎么做?
我的解决方案
for i in range(0,len(df.index)):
x = 0
x = ((df['A'].iloc[i]-df['A'].iloc[i-1])/
(df['B'].iloc[i]-df['B'].iloc[i-1]))
print(x)
df['C'][i] = x
print(df['C'])
输出是:
# Below is output of print(x)
-108.36672934277205
1290.5898665696209
-33.6996594301328
-65.35882129611214
.
.
.
267.5508063249828
-59.56361658427877
-91.13780524775356
-15.836441236656086
38.48640472603791
-145.4802310927083
# Below is output of print(df['C'])
2019-01-25 08:15:00 -145.480231
2019-01-25 08:30:00 -145.480231
2019-01-25 08:45:00 -145.480231
2019-01-25 09:00:00 -145.480231
.
.
.
.
.
.
.
2019-03-08 09:00:00 -145.480231
2019-03-08 09:15:00 -145.480231
2019-03-08 09:30:00 -145.480231
2019-03-08 09:45:00 -145.480231
我的for循环函数成功计算。 但是我无法将每个值存储在相应的行中。 相反,我的函数将最后计算的值(-145.48)放在所有行中。 怎么解决?
希望这可以帮助:
x = []
for i in range(0,len(df)):
x.insert(len(x),(df.iloc[i][1]-df.iloc[i-1][1])/(df.iloc[i][2]-df.iloc[i-1][2]))
df["C"] = x
要查看结果:
print(df)
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.