我收到类型错误，但不确定为什么吗？

Question

我不知道为什么此代码返回类型错误

if response == "1":
   return print(" You've selected the Bundle Package! Please schedule a home visit and our technician will come and set up your new service.") + home_visit("new install")  

TypeError：+不支持的操作数类型：“ NoneType”和“ str”

是因为我试图调用一个函数以及打印一条语句吗？

Answer 1

这是因为打印不返回任何内容。 它只是打印。 如果您想返回print + home_visit，则：

return f"You've selected the Bundle Package! Please schedule a home visit and our technician will come and set up your new service.{home_visit('new install')}"

Answer 2

这可能是您的误解。 返回print（）不会返回包含它的字符串。 如果您仍想在其中打印字符串，然后调用该函数，然后将打印的字符串返回到调用它的位置，则可以这样进行：

if response == "1":
   # this is the string you want
   whatIWantToPrint = " You've selected the Bundle Package! Please schedule a home visit and our technician will come and set up your new service."
   # this is where you print it
   print(whatIWantToPrint)
   # this is where you call the function
   home_visit("new install")
   # this is where you return the string you printed
   return whatIWantToPrint

Answer 3

该错误表明您正在尝试合并返回的输出，即NoneType和一个字符串。 您应该先打印然后返回字符串。 这是一个例子：

if response == "1":
    print(" You've selected the Bundle Package! Please schedule a home visit and our technician will come and set up your new service.")
    return home_visit("new install")