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Django ModelForm:如何在下拉字段中显示用户特定的数据?

[英]Django ModelForm: How to display user specific data in a drop-down field?

我有一个名为Label的下拉字段,作为名为Birthday的模型的一部分。 我的问题是,下拉字段显示所有用户的标签。 如何确保它仅显示特定于用户的标签?

我假设在表单模型中需要查询,但是我不知道如何执行此操作。

形式

class BirthdayForm(forms.ModelForm):

    class Meta:
        model = Birthday
        fields = ('name', 'day', 'label')

class LabelForm(forms.ModelForm):

    class Meta:
        model = Label
        fields = ('tag',)

楷模

class Label(models.Model):
    user = models.ForeignKey(settings.AUTH_USER_MODEL, on_delete=models.CASCADE)
    tag = models.CharField(max_length=25)

    def __str__(self):
        return self.tag

class Birthday(models.Model):
    user = models.ForeignKey(settings.AUTH_USER_MODEL, on_delete=models.CASCADE)
    name = models.CharField(max_length=25, default="")
    day = models.DateField()
    label = models.ForeignKey(Label, on_delete=models.SET_NULL, default=0, null=True, blank=True) 

    def __str__(self):  
        return self.name

视图

@login_required
def index(request):
    if request.method == "POST":
        form = BirthdayForm(request.POST)
        if form.is_valid():
            birthday = form.save(commit=False)
            birthday.user = request.user
            birthday.save()
            return redirect('index')
    else:
        form = BirthdayForm()
    birthday = Birthday.objects.filter(user=request.user)
    username = request.user
    return render(request, 'bd_calendar/index.html', {'form': form, 'birthday': birthday, 'username': username })

模板

            <form method="POST">{% csrf_token %}
                <table border="0">
                    {{ form }}
                </table>
                <button class="submitButton" type="submit">Submit</button>
            </form>

尝试这个

class BirthdayForm(forms.ModelForm):

    class Meta:
        model = Birthday
        fields = ('name', 'day', 'label')
    def __init__(self, user, *args, **kwargs):
        super(BirthdayForm, self).__init__(*args, **kwargs)
        self.fields['label'].queryset = Label.objects.filter(user=user)

希望能帮助到你

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