[英]troubles on “over partition by”
我必须对使用以下类型的查询与数据库接口的现有代码(java)进行更改:
select distinct
u.id_anauser,
u.usestate,
count(*) over (partition by u.usestate , id_anauser) cnt
from
services u
因为不允许我进行单独的查询并通过工作Java端或翻转查询来关联结果(否则,我将切换到亲爱的旧“ group by”,即使使用,我也可以获得一些信息)肯定是更长更复杂的旅程),我添加了以下内容:
...
where (
u.usestate = 1
or
u.usestate = 3)
它起作用了,但是问题是这样,我得到了,当同一个“ id_ana”同时与“ usestate = 1”和“ usestate = 3”相关联时,双行与同一个“ id_ana”相关联,这是不允许的:我可以随意添加列。 所以我想做这样的事情:
select distinct
u.id_anauser,
u.usestate,
count(*) over (partition by u.usestate = 1 , id_anauser) cnt1,
count(*) over (partition by u.usestate = 3 , id_anauser) cnt2
from
services u
但是我找不到正确的语法! (我是“ javer”,而不是“ SQLer” :-))
使用条件聚合:
select distinct
u.id_anauser,
u.usestate,
sum(case when u.usestate = 1 then 1 else 0 end) over (partition by id_anauser) as cnt1,
sum(case when u.usestate = 3 then 1 else 0 end) over (partition by id_anauser) as cnt3
from services u;
我不明白为什么您要在此查询中使用select distinct
。
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