[英]troubles on “over partition by”
我必須對使用以下類型的查詢與數據庫接口的現有代碼(java)進行更改:
select distinct
u.id_anauser,
u.usestate,
count(*) over (partition by u.usestate , id_anauser) cnt
from
services u
因為不允許我進行單獨的查詢並通過工作Java端或翻轉查詢來關聯結果(否則,我將切換到親愛的舊“ group by”,即使使用,我也可以獲得一些信息)肯定是更長更復雜的旅程),我添加了以下內容:
...
where (
u.usestate = 1
or
u.usestate = 3)
它起作用了,但是問題是這樣,我得到了,當同一個“ id_ana”同時與“ usestate = 1”和“ usestate = 3”相關聯時,雙行與同一個“ id_ana”相關聯,這是不允許的:我可以隨意添加列。 所以我想做這樣的事情:
select distinct
u.id_anauser,
u.usestate,
count(*) over (partition by u.usestate = 1 , id_anauser) cnt1,
count(*) over (partition by u.usestate = 3 , id_anauser) cnt2
from
services u
但是我找不到正確的語法! (我是“ javer”,而不是“ SQLer” :-))
使用條件聚合:
select distinct
u.id_anauser,
u.usestate,
sum(case when u.usestate = 1 then 1 else 0 end) over (partition by id_anauser) as cnt1,
sum(case when u.usestate = 3 then 1 else 0 end) over (partition by id_anauser) as cnt3
from services u;
我不明白為什么您要在此查詢中使用select distinct
。
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