如何根据用户对第一个问题的输入提示用户 x 次
[英]How do I promt user x amount of times based on their input on the first question
问题描述
我正在做调度，通过他们的名字得到用户的输入，在他们有机会获得工作和什么样的工作＃那些。 我的问题是，如果# of jobs == 4，那么， kind of jobs应该提示用户 4 次，但由于它们都在自己的函数中，因此# of jobs重置，这使得某种作业只提示一次。
我试过的，将它们组合在一个函数中，这样# of jobs就不会重置并进行 for 循环，而是显示 4 次而不是提示用户；
How many jobs do you have access in? (1-4): 2
---------------------------------------------------------------------------
Please, TYPE: SMT, TEST, REWORK, BOX BUILD, SHIPPING & WASH: wash
---------------------------------------------------------------------------
['Marc', 'WASH']
---------------------------------------------------------------------------
['Marc', 'WASH', 'WASH']
---------------------------------------------------------------------------
None
---------------------------------------------------------------------------
预期的结果是；
How many jobs do you have access in? (1-4): 2
---------------------------------------------------------------------------
Please, TYPE: SMT, TEST, REWORK, BOX BUILD, SHIPPING & WASH: SMT
---------------------------------------------------------------------------
Please, TYPE: SMT, TEST, REWORK, BOX BUILD, SHIPPING & WASH: TEST
---------------------------------------------------------------------------
["SMT","TEST"]
---------------------------------------------------------------------------
full_employee = []
def employee_name_input():
while True:
employee_name = str(input("Enter your first name: ")).strip().capitalize()
if not employee_name.isalpha():
print("Invalid input. Please try again!")
else:
full_employee.insert(0,employee_name)
return access_jobs_input()
def access_jobs_input():
access_num = int(input("How many jobs do you have access in? (1-4): "))
if access_num <= 4:
access_jobs = str(input("Please, TYPE: SMT, TEST, REWORK, BOX BUILD, SHIPPING & WASH: ")).strip().upper()
for num in range(access_num):
full_employee.append(access_jobs)
print(full_employee)
if not access_jobs.isalpha():
print("Your input is invalid. Please try again")
return access_jobs_input()
else:
print ("You are entering more than 4 access and it is not authorized. Please try again!")
return access_jobs_input()
1 个解决方案
解决方案1
1 已采纳 2019-04-27 05:28:00
您的代码有一些问题，我将在下面概述。
- 您正在添加每个作业
access_num次，但您只需添加一次。 - 使用 while 循环而不是递归来确保输入仅执行
access_num次，并且输入无效。 - 在您的函数中定义
full_employee，并实际调用该函数以使其工作 - 检查条件是否大于等于 1
- 通过将输入与有效作业列表进行比较来检查输入是否有效，而不是检查
isalphanum - 您的
employee_name_input函数应该返回一个字符串 - 如果名称中有空格，则名称的
isalpha将不起作用，除非您只想要名字而没有任何空格
下面的代码应该适合你。 查看评论以了解正在发生的事情
def employee_name_input():
employee_name = ''
#Try till you get a valid name
while True:
employee_name = str(input("Enter your first name: ")).strip().capitalize()
#Ask to retry if invalid name, else break the loop
if not employee_name.isalpha():
print("Invalid input. Please try again!")
else:
break
#Return name of employee
return employee_name
def access_jobs_input():
#List to hold input of jobs
full_employee = []
#List of valid jobs
valid_jobs = ['SMT', 'TEST', 'REWORK', 'BOX BUILD', 'SHIPPING', 'WASH']
#Try until valid access number is provided
while True:
# Get number of jobs
access_num = int(input("How many jobs do you have access in? (1-4): "))
#If access num is between 1 and 4
if 1 <= access_num <= 4:
idx = 0
#While access_num jobs are provided
while idx < access_num:
access_jobs = str(input("Please, TYPE: SMT, TEST, REWORK, BOX BUILD, SHIPPING & WASH: ")).strip().upper()
#If entered job is invalid, don't increment the index and ask to try again
if access_jobs not in valid_jobs:
print("Your input is invalid. Please try again")
#If entered job is valid, append it to input of jobs and increment index
else:
full_employee.append(access_jobs)
idx+=1
return full_employee
#Else return empty list
else:
print("You are entering invalid number of access and it is not authorized. Please try again!")
employee_name = employee_name_input()
access_jobs = access_jobs_input()
result = [employee_name]+access_jobs
print(result)
可能的输出将是。
How many jobs do you have access in? (1-4): -1
You are entering invalid number of access and it is not authorized. Please try again!
How many jobs do you have access in? (1-4): 5
You are entering invalid number of access and it is not authorized. Please try again!
Enter your first name: decenttaro
How many jobs do you have access in? (1-4): 2
Please, TYPE: SMT, TEST, REWORK, BOX BUILD, SHIPPING & WASH: SMT
Please, TYPE: SMT, TEST, REWORK, BOX BUILD, SHIPPING & WASH: WASH
['Decenttaro', 'SMT', 'WASH']
How many jobs do you have access in? (1-4): 3
Please, TYPE: SMT, TEST, REWORK, BOX BUILD, SHIPPING & WASH: XYZ
Your input is invalid. Please try again
Please, TYPE: SMT, TEST, REWORK, BOX BUILD, SHIPPING & WASH: ABC
Your input is invalid. Please try again
Please, TYPE: SMT, TEST, REWORK, BOX BUILD, SHIPPING & WASH: BOX BUILD
Please, TYPE: SMT, TEST, REWORK, BOX BUILD, SHIPPING & WASH: XYZ
Your input is invalid. Please try again
Please, TYPE: SMT, TEST, REWORK, BOX BUILD, SHIPPING & WASH: WASH
Please, TYPE: SMT, TEST, REWORK, BOX BUILD, SHIPPING & WASH: ABC
Your input is invalid. Please try again
Please, TYPE: SMT, TEST, REWORK, BOX BUILD, SHIPPING & WASH: REWORK
['BOX BUILD', 'WASH', 'REWORK']
Enter your first name: Decenttaro
How many jobs do you have access in? (1-4): 5
You are entering invalid number of access and it is not authorized. Please try again!
How many jobs do you have access in? (1-4): -1
You are entering invalid number of access and it is not authorized. Please try again!
How many jobs do you have access in? (1-4): 2
Please, TYPE: SMT, TEST, REWORK, BOX BUILD, SHIPPING & WASH: SMT
Please, TYPE: SMT, TEST, REWORK, BOX BUILD, SHIPPING & WASH: WASH
['Decenttaro', 'SMT', 'WASH']
Enter your first name: Decenttaro
How many jobs do you have access in? (1-4): 5
You are entering invalid number of access and it is not authorized. Please try again!
How many jobs do you have access in? (1-4): -1
You are entering invalid number of access and it is not authorized. Please try again!
How many jobs do you have access in? (1-4): 2
Please, TYPE: SMT, TEST, REWORK, BOX BUILD, SHIPPING & WASH: SMT
Please, TYPE: SMT, TEST, REWORK, BOX BUILD, SHIPPING & WASH: WASH
['Decenttaro', 'SMT', 'WASH']
当用户为变量分配了用户选择输入的“ x”次次数时，如何创建变量？
[英]How do I create variables as they are being assigned by the user a 'x' amount of times that the user chooses to input?
你如何让 Python 向用户询问输入“x”的次数？
[英]How do you get Python to ask the user for an input 'x' amount of times?
我如何从列表中随机选择用户要求在 python 中使用输入的次数？
[英]how do i randomly pick characters out of a list the amount of times the user asks for using input in python?
如何进行验证循环以确保用户在 a.split 输入中输入正确的次数？
[英]How do I make a validation loop to make sure the user inputs the correct amount of times in a .split input?
是否有一种简单的方法可以将用户输入作为整数使用，并将该整数用作下一个问题被问多少次的量？
[英]Is there a simple way to take user input as an integer and use that integer as an amount for how many times the next question is asked?
如何根据上一个函数的用户输入使下一个输入问题重复多次
[英]how to make next input question repeat a number of times based on user input from previous function
Python：如何获得一个程序来提示用户一定的固定时间来输入用户信息？
[英]Python: How do you get a programme to prompt the user a certian fixed amount of times for a user input?
声明:本站的技术帖子网页，遵循CC BY-SA 4.0协议，如果您需要转载，请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.