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当我运行我的Python Turtle游戏时,图形窗口停止响应

[英]When I run my Python Turtle game, the Graphics Window stops responding

我是乌龟和编程的新手,想做一个标记游戏。 有两个用户,其中一个是跑步者,一个是追逐者(鲍勃和菲尔)。 当追踪器靠近跑步者(使用距离公式检测到)时,程序将它们设置回原始起始位置。 但是,每当我运行程序时,Turtle Graphics窗口会冻结并停止响应,最终导致我关闭程序。 任何人都可以帮我识别问题吗?

import turtle
import math
bob = turtle.Turtle()

wn = turtle.Screen()
wn.bgcolor("black")
wn.setup(width = 700, height = 700)
wn.tracer()

border_pen = turtle.Turtle()
border_pen.speed(0)
border_pen.color("white")
border_pen.penup()
border_pen.setposition(-300,-300)
border_pen.pendown()
border_pen.pensize(3)
for side in range(4):
    border_pen.fd(600)
    border_pen.lt(90)
border_pen.hideturtle()

bob.shape("triangle")
bob.speed(0)
bob.color("blue")
bob.penup()
bob.setpos(-50, 0)
def draw():
    bob.penup()
def nodraw():
    bob.pendown()

def fd():
    bob.fd(20)
    if bob.xcor() > 280:
        bob.setx(280)
    if bob.ycor() > 280:
        bob.sety(280)

    if bob.xcor() < -280:
        bob.setx(-280)
    if bob.ycor() <- 280:
        bob.sety(-280)
def right():
    bob.right(90)

def left():
    bob.left(90)

turtle.listen()
turtle.onkey(left, "Left")
turtle.onkey(fd, "Up")
turtle.onkey(right, "Right")

phil = turtle.Turtle()
phil.speed(0)
phil.penup()
phil.shape("triangle")
phil.color("red")
phil.setpos(50, 0)

def fdp():
    phil.fd(20)
    if phil.xcor() > 280:
        phil.setx(280)
    if phil.ycor() > 280:
        phil.sety(280)

    if phil.xcor() < -280:
        phil.setx(-280)
    if phil.ycor() <- 280:
        phil.sety(-280)
def rightp():
    phil.right(90)

def leftp():
    phil.left(90)

turtle.listen()
turtle.onkey(leftp, "a")
turtle.onkey(fdp, "w")
turtle.onkey(rightp, "d")


def isCollision(t1, t2):
    distance = math.sqrt(math.pow(t1.xcor()-t2.xcor(),2)+math.pow(t1.ycor()-t2.ycor(),2))
    if distance < 20:
        return True
    else:
        return False
while True:
    if isCollision(bob, phil):
        bob.setposition(-50, 0)
        phil.setposition(50, 0)



turtle.done()

经过审核,这应该工作:

import turtle
import math

bob = turtle.Turtle()

wn = turtle.Screen()
wn.bgcolor("black")
wn.setup(width = 700, height = 700)
wn.tracer()

border_pen = turtle.Turtle()
border_pen.speed(0)
border_pen.color("white")
border_pen.penup()
border_pen.setposition(-300,-300)
border_pen.pendown()
border_pen.pensize(3)

for side in range(4):
    border_pen.fd(600)
    border_pen.lt(90)
border_pen.hideturtle()

bob.shape("triangle")
bob.speed(0)
bob.color("blue")
bob.penup()
bob.setpos(-50, 0)
def draw():
    bob.penup()
def nodraw():
    bob.pendown()

def fd():
    bob.fd(20)
    if bob.xcor() > 280:
        bob.setx(280)
    if bob.ycor() > 280:
        bob.sety(280)

    if bob.xcor() < -280:
        bob.setx(-280)
    if bob.ycor() <- 280:
        bob.sety(-280)
    distance = math.sqrt(math.pow(bob.xcor()-phil.xcor(),2)+math.pow(bob.ycor()-phil.ycor(),2))
    print(distance)
    if distance < 20:
        bob.setposition(-50, 0)
        phil.setposition(50, 0)
def right():
    bob.right(90)

def left():
    bob.left(90)

turtle.listen()
turtle.onkey(left, "Left")
turtle.onkey(fd, "Up")
turtle.onkey(right, "Right")

phil = turtle.Turtle()
phil.speed(0)
phil.penup()
phil.shape("triangle")
phil.color("red")
phil.setpos(50, 0)

def fdp():
    phil.fd(20)
    if phil.xcor() > 280:
        phil.setx(280)
    if phil.ycor() > 280:
        phil.sety(280)

    if phil.xcor() < -280:
        phil.setx(-280)
    if phil.ycor() <- 280:
        phil.sety(-280)
def rightp():
    phil.right(90)

def leftp():
    phil.left(90)

turtle.listen()
turtle.onkey(leftp, "a")
turtle.onkey(fdp, "w")
turtle.onkey(rightp, "d")

turtle.done()

将你的turtle.done()缩进到while循环中。 这将解决你的冰冻问题。 像这样 :

while True:
    if isCollision(bob, phil):
        bob.setposition(-50, 0)
        phil.setposition(50, 0)
    turtle.done()

你也可以删除while循环,因为你的if语句不需要它。 像这样:

if isCollision(bob, phil):
    bob.setposition(-50, 0)
    phil.setposition(50, 0)
turtle.done()

您的原始代码和我在下面尝试解决的建议答案存在问题。 具体来说:你不需要计算海龟之间的距离,他们已经知道如何做到这一点; 你和其他人使用tracer()毫无意义,因为你没有update()调用; 鲍勃和菲尔之间的碰撞应该是对称的,但其中一个答案认为鲍勃与菲尔碰撞但不与菲尔碰撞鲍勃; 其中一个答案似乎不了解turtle.done()的本质。

from turtle import Screen, Turtle, mainloop

def bob_left():
    bob.left(90)

def bob_forward():
    bob.forward(20)

    if bob.xcor() > 280:
        bob.setx(280)
    elif bob.xcor() < -280:
        bob.setx(-280)

    if bob.ycor() > 280:
        bob.sety(280)
    elif bob.ycor() < -280:
        bob.sety(-280)

    checkCollision()

def bob_right():
    bob.right(90)

def phil_left():
    phil.left(90)

def phil_forward():
    phil.forward(20)

    if phil.xcor() > 280:
        phil.setx(280)
    elif phil.xcor() < -280:
        phil.setx(-280)

    if phil.ycor() > 280:
        phil.sety(280)
    elif phil.ycor() < -280:
        phil.sety(-280)

    checkCollision()

def phil_right():
    phil.right(90)

def isCollision(t1, t2):
    return t1.distance(t2) < 20

def checkCollision():
    if isCollision(bob, phil):
        bob.setposition(-50, 0)
        phil.setposition(50, 0)

screen = Screen()
screen.bgcolor('black')
screen.setup(width=700, height=700)

border_pen = Turtle(visible=False)
border_pen.speed('fastest')
border_pen.color('white')
border_pen.pensize(3)

border_pen.penup()
border_pen.setposition(-300, -300)
border_pen.pendown()

for _ in range(4):
    border_pen.fd(600)
    border_pen.lt(90)

bob = Turtle('triangle')
bob.speed('fastest')
bob.color('blue')
bob.penup()
bob.setpos(-50, 0)

phil = Turtle('triangle')
phil.speed('fastest')
phil.color('red')
phil.penup()
phil.setposition(50, 0)

screen.onkey(bob_left, 'Left')
screen.onkey(bob_forward, 'Up')
screen.onkey(bob_right, 'Right')

screen.onkey(phil_left, 'a')
screen.onkey(phil_forward, 'w')
screen.onkey(phil_right, 'd')
screen.listen()

mainloop()

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