[英]Validation error of type SubSelectionRequired: Sub selection required for type Timestamp of field
我使用 GraphQL-SPQR 库问题是“SubSelectionRequired 类型的验证错误:Timestamp 类型需要子选择”也许在查询中存在对 Entity 中的时间戳或格式的表达式
{"query":
"{findUserPointByUserId(userId:73){rowNum userAccountPointUserId totalPoint pointTypeDescription point userAccountCreatedDate} findUserAccountImgByUserId(userId:73){imageId,userId,presentImgNum}}"
}
错误
{
"errors": [
{
"message": "Validation error of type SubSelectionRequired: Sub selection required for type Timestamp of field userAccountCreatedDate",
"locations": [
{
"line": 1,
"column": 103
}
]
}
]
}
实体
@NoArgsConstructor
@AllArgsConstructor
@Getter
@Setter
@Entity
@Table(name = "view_user_account_point", schema = "public", catalog = "corus")
public class ViewUserAccountPoint {
@Id
@Basic
@GraphQLQuery(name = "rowNum")
@Column(name = "row_num", nullable = true)
private Long rowNum;
@Basic
@Column(name = "user_account_point_userid", nullable = true)
@GraphQLQuery(name = "userAccountPointUserId")
private Integer userAccountPointUserId;
@Basic
@Column(name = "subject_id", nullable = true)
@GraphQLQuery(name = "subjectId")
private Integer subjectId;
@Basic
@Column(name = "point", nullable = true)
@GraphQLQuery(name = "point")
private Integer point;
@Basic
@Column(name = "user_account_point_typeid", nullable = true)
@GraphQLQuery(name = "userAccountPointTypeId")
private Integer userAccountPointTypeId;
@Basic
@Column(name = "date_created", nullable = true)
@GraphQLQuery(name = "userAccountCreatedDate")
private Timestamp userAccountCreatedDate;
服务
public List<ViewUserAccountPoint> findUserPointByUserId(@GraphQLArgument(name = "userId") Integer userId){
return viewUserAccountPointRepository.findByUserAccountPointUserIdOrderByUserAccountCreatedDateDesc(userId);
}
控制器
private final GraphQL graphQL;
public UserController(UserAccountService userAccountService) {
GraphQLSchema schema = new GraphQLSchemaGenerator()
.withResolverBuilders(
//Resolve by annotations
new AnnotatedResolverBuilder())
.withOperationsFromSingleton(userAccountService,UserAccountService.class)
.withValueMapperFactory(new JacksonValueMapperFactory())
.generate();
graphQL = GraphQL.newGraphQL(schema).build();
}
@PostMapping(value = "/graphql", consumes = MediaType.APPLICATION_JSON_UTF8_VALUE, produces = MediaType.APPLICATION_JSON_UTF8_VALUE)
@ResponseBody
public Map<String, Object> graphql(@RequestBody Map<String, String> request, HttpServletRequest raw) {
ExecutionResult executionResult = graphQL.execute(ExecutionInput.newExecutionInput()
.query(request.get("query"))
.operationName(request.get("operationName"))
.context(raw)
.build());
return executionResult.toSpecification();
}
我搜索了所有查询时间戳格式但是,我找不到我希望听到解决方案。 谢谢你
出于某种原因, Timestamp
被错误地映射。 它最终成为一个对象而不是标量。 正如您在打开的问题中提到的,目前还不清楚您的代码中的Timestamp
来自哪里。
GraphQL SPQR 的最新版本支持java.sql.Timestamp
,因此您可能使用的是旧版本。
如果不是这种情况,则意味着Timestamp
不是java.sql.Timestamp
,您需要为它注册一个自定义映射器。
public class TimestampMapper implements TypeMapper {
// Define the scalar as needed, see io.leangen.graphql.util.Scalars for inspiration
private static final GraphQLScalarType TIMESTAMP = ...;
@Override
public GraphQLOutputType toGraphQLType(AnnotatedType javaType, OperationMapper operationMapper, Set<Class<? extends TypeMapper>> mappersToSkip, BuildContext buildContext) {
return TIMESTAMP; //it's important to always return the same instance
}
@Override
public GraphQLInputType toGraphQLInputType(AnnotatedType javaType, OperationMapper operationMapper, Set<Class<? extends TypeMapper>> mappersToSkip, BuildContext buildContext) {
return TIMESTAMP; //same as above
}
@Override
public boolean supports(AnnotatedType type) {
return ClassUtils.isSuperClass(Timestamp.class, type);
}
}
然后注册您的映射器:
generator.withTypeMappers(new TimestampMapper())
对于我的情况,这是不正确的查询正文,请确保您拥有正确的查询正文。
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