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[英]Django Rest Framework nested relationship performance on SerializerMethodField
[英]Django nested serializer with serializermethodfield
我有一个API端点api/v1/checkin/
,它返回当前DeviceGroup
和必须处于活动状态的App
的AppVersions
。
端点当前返回数据以及正确过滤的AppVersions
如下所示:
{
"customer_device_uuid": "8d252b78-6785-42ea-9aee-b6f9e0f870b5",
"device_group": {
"group_uuid": "869b409d-f281-492e-bb62-d3168aea4394",
"device_group_name": "Default",
"color": "#0a2f45",
"is_default": true,
"app_versions": [
"2.0",
"1.1"
]
}
}
我希望响应中的app_versions
包含更多这样的数据:
{
"customer_device_uuid": "8d252b78-6785-42ea-9aee-b6f9e0f870b5",
"device_group": {
"group_uuid": "869b409d-f281-492e-bb62-d3168aea4394",
"device_group_name": "Default",
"color": "#0a2f45",
"is_default": true,
"app_versions": [
{
"app_version_uuid": "UUID here",
"app_version_name": "1.1",
"package_id": "package name here",
"auto_start": false,
"version_code": 1,
"version_name": "0.1",
"source": "link to file here"
}, ...
]
}
}
# serializers.py
class AppVersionSerializer(serializers.ModelSerializer):
auto_start = serializers.BooleanField(source='app_uuid.auto_start')
class Meta:
model = AppVersion
fields = ('app_version_uuid', 'app_version_name', 'package_id', 'auto_start', 'version_code', 'version_name',
'source')
class DeviceGroupSerializer(serializers.ModelSerializer):
app_versions = serializers.SerializerMethodField(read_only=True)
# filters the app versions per app
def get_app_versions(self, model):
qs = model.get_current_app_versions()
return [o.app_version_name for o in qs]
class Meta:
model = DeviceGroup
fields = ('group_uuid', 'device_group_name', 'color', 'is_default', 'app_versions')
class CheckinSerializer(serializers.ModelSerializer):
device_group = DeviceGroupSerializer(many=False, read_only=True, source='group_uuid')
class Meta:
model = CustomerDevice
fields = ('customer_device_uuid', 'customer_uuid', 'device_id_android', 'device_group')
extra_kwargs = {
'customer_uuid': {'write_only': True},
'device_id_android': {'write_only': True}
}
我猜想我必须更改get_app_versions()
才能实现我的目标,但我不知道如何实现。
为了获得所需的响应,我应该改变什么?
执行过滤的get_current_app_versions
方法
# models.py
def get_current_app_versions(self):
return (
AppVersion.objects
.filter(appversiondevicegrouplink__release_date__lt=timezone.now())
.filter(appversiondevicegrouplink__device_group=self)
.order_by('app_uuid__app_uuid', '-appversiondevicegrouplink__release_date')
.distinct('app_uuid__app_uuid')
)
假设您必须更改get_app_versions
是正确的,而不是返回return [o.app_version_name for o in qs]
行中的列表),您将需要返回字典列表。
您将需要为AppVersions
模型创建完整的序列化器。 然后在get_app_versions
正确地序列化您的返回值,方法是将它们传递到新的序列化器中,该序列化器包含您要返回的所有字段return AppVersionSerializer2(qs, many=True).data
。
您可能必须重写某些字段的序列化,因为序列化程序可能无法很好地自动处理它们。
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