[英]Regex for capturing digits in a string (Python)
我是python的新手,正在处理带有正则表达式的文本文件以提取id和附加列表。 我在下面写了一些python,打算构造一个像这样的列表
["10073710","10074302","10079203","10082213"...and so on]
相反,我看到的是一个列表结构,其中包含许多冗长的标签。 我假设这是正常行为,并且finditer函数在找到匹配项时会追加这些标签。 但是响应有点混乱,我不确定如何关闭/删除这些添加的标签。 请参见下面的屏幕截图。
谁能帮我修改下面的代码,以便实现列表的预期结构?
import re
#create a list of strings
company_id = []
#open file contents into a variable
company_data = open(r'C:\Users\etherealessence\Desktop\company_data_test.json', 'r', encoding="utf-8")
#read the line structure into a variable
line_list = company_data.readlines()
#stringify the contents so regex operations can be performed
line_list = str(line_list)
#close the file
company_data.close()
#assign the regex pattern to a variable
pattern = re.compile(r'"id":([^,]+)')
#find all instances of the pattern and append the list
#https://stackoverflow.com/questions/12870178/looping-through-python-regex-matches
for id in re.finditer(pattern, line_list):
#print(id)
company_id.append(id)
#test view the list of company id strings
#print(line_list)
print(company_id)
re.finditer
返回re.Match
对象的iterator
。
如果要提取实际匹配项(更具体地说,是捕获的组,以摆脱开头的"id":
:),则可以执行以下操作:
for match in re.finditer(pattern, line_list):
company_id.append(match.group(1))
要获取值,请使用id.string
:
for id in re.finditer(pattern, line_list):
company_id.append(id.string)
因为当您仅读取id时,您并未获取实际值。
如果您的数据使用JSON,则可能只想简单地对其进行分析。
如果希望使用正则表达式,则可以简化表达式,并使用三个捕获组轻松获得所需的ID。 您可以在ID的左侧和右侧设置两个捕获组,然后中间的捕获组可以帮助您获取ID,也许类似于以下表达式 :
("id":")([0-9]+)(")
该链接可帮助您形象化您的表情:
# coding=utf8
# the above tag defines encoding for this document and is for Python 2.x compatibility
import re
regex = r"(\x22id\x22:\x22)([0-9]+)(\x22)"
test_str = "some other JSON data'\"id\":\"10480132\"'>some other JSON datasome other JSON data'\"id\":\"10480132\"'>some other JSON datasome other JSON data'\"id\":\"10480132\"'>some other JSON datasome other JSON data'\"id\":\"10480132\"'>some other JSON datasome other JSON data'\"id\":\"10480132\"'>some other JSON data"
matches = re.finditer(regex, test_str, re.MULTILINE)
for matchNum, match in enumerate(matches, start=1):
print ("Match {matchNum} was found at {start}-{end}: {match}".format(matchNum = matchNum, start = match.start(), end = match.end(), match = match.group()))
for groupNum in range(0, len(match.groups())):
groupNum = groupNum + 1
print ("Group {groupNum} found at {start}-{end}: {group}".format(groupNum = groupNum, start = match.start(groupNum), end = match.end(groupNum), group = match.group(groupNum)))
# Note: for Python 2.7 compatibility, use ur"" to prefix the regex and u"" to prefix the test string and substitution.
# -*- coding: UTF-8 -*-
import re
string = "some other JSON data'\"id\":\"10480132\"'>some other JSON datasome other JSON data'\"id\":\"10480132\"'>some other JSON datasome other JSON data'\"id\":\"10480132\"'>some other JSON datasome other JSON data'\"id\":\"10480132\"'>some other JSON datasome other JSON data'\"id\":\"10480132\"'>some other JSON data"
expression = r'(\x22id\x22:\x22)([0-9]+)(\x22)'
match = re.search(expression, string)
if match:
print("YAAAY! \"" + match.group(2) + "\" is a match 💚💚💚 ")
else:
print('🙀 Sorry! No matches!')
YAAAY! "10480132" is a match 💚💚💚
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