用python中的随机值替换列表中的随机元素

Question

我将以下一组值存储在列表中。

[-1.7683218, 0.22206295, -0.28429198, 5.925369, -3.952484, -3.0728238, 0.09690776, -0.31914753, 3.9695702, 26.934353, 1.4882066, 1.8194668, -0.5614318, 1.2354431, -0.09714768, -0.15579335, -0.059994906, 1.0105655, -23.25607, 31.982368, -0.09390785, 0.17786688, 0.36164832, -4.673975, 13.495866, -3.57134, 0.5583399, -1.801314, 2.4207468, 2.0513844, -3.429592, -9.599998, 23.412394, -3.963623, 6.930485, 2.5186272, 0.6805691, -1.1615586, -0.915736, -2.6307302, -14.409785, 0.6327307, 10.512744, -0.09292421, -0.61977243, 0.35928893, -1.3844814, 8.098062, -0.8270248, 0.47219157, 0.089366496, 0.9056338, 1.5297629, 3.3246832, -0.9748858, 36.62332, -1.0525678, -0.87139374, 6.7600174, 36.210625, -0.25728267, 14.568578, 0.87466383, -4.2237897, -5.4309, 19.762472, 0.8426512, -0.7807278, 0.03435099, 12.787761, -4.9308186, -1.4322343, 0.49790275, -12.979129, 0.18121482, -0.81953144, -1.5393608, 17.757078, 3.5726204, -11.319154, -0.002896044, -1.8806648, 0.30027565, -2.6210017, 16.230186, -2.2566936, 37.37506, -2.7738526, -0.91440165, -3.652771, 1.8378688, -0.25519317, 0.5222581, 0.2189773, 23.825306, 0.3779062, 2.6709516, 0.84001434, -0.41394734, -0.600579, -3.1629875, 0.2880843, -3.9132822, 5.674796, -0.5569526, 0.30253112, -4.4269695, 4.5206604, -0.8477638, 0.0032483074, -2.2814171, 0.5524869, -1.4271426, -0.24263692, 1.0095457, -3.187037, -1.6656531, 1.4805393, 0.064992905, -4.8124804, -0.07194552, -0.28692132, -0.19502515, 0.010771384, -32.744797, 1.2642047, 6.3942785, -1.2971659, 29.70087, 0.19707158, -2.734262, 2.8497686, -1.710305, -1.3836008, 22.758884, -1.8488939, 4.1740856, 0.26019523, -8.814447, -3.937495, 0.22731477, -0.7874651, 17.22002, -7.89242, -0.5795766, 3.3960745, 1.0440702, 0.5483718, 1.2849183, -0.63732344, -40.38428, -4.25527, 3.034935, 0.25527972, -0.81940174, -7.0720696, 1.7420169, 14.904871, -1.5399592, 0.20110837, 0.1902977, 2.5790472, -28.560707, 0.09560776, -0.973604, 0.6214314, -5.1268454, -0.9104073, 33.082394, 0.23800176, -9.696023, 12.288443, -16.52249, -7.6811, -21.928356, 25.690449, -0.6803232, -1.4738222, -1.831514, 0.00013296002, -3.1330614, 3.6067219, -3.0617614, -6.334016, -24.856865, -6.0669985, 2.8829474, 0.76423097, -0.21836776, -2.3173273, -2.092735, -0.19577695, 4.2984896, 0.029742926, 1.0902604, -0.28707412, -0.1671038, -0.4607489, -15.966867, -1.7149612, -1.3445716, 1.400264, 4.906401, -6.314724, -0.92188597, -0.14341217, -6.819194, 1.2750683, 21.634096, 0.5503013, 5.2122655, -0.096101895, -0.69029164, 2.6239898, -26.33101, -3.7901835, 10.026649, 1.0661886, 0.8891293, 34.24628, -0.9036363, -4.4846773, -30.846636, -5.8609247, -0.018534392, 4.657759e-06, 16.96108, 10.725708, -0.3170653, -3.2331817, 0.73887914, 0.69840825, 0.9043666, 1.0727708, 1.6571997, -0.70257163, 2.4863558, 0.07501343, -35.059708, 0.72496796, -3.0723267, -3.2004805, -0.9447444, 0.56954986, 2.6018164, -0.49256825, 22.71359, 0.45523545, -2.1936522, 4.008838, 0.62327665, 10.315046, 1.4006382, 1.1290226, 1.2660133, -8.46607]

我希望能够再创建 100 个与此类似的列表，但在原始列表的最高和最低值中包含随机选择的不同随机值。 让我们考虑一个较小的例子来更好地理解这个问题。 让我们考虑一下我有最高最低值 -1 和最高值 7.2 的列表。

original list   :  [0.5, 0.8, 1.1, 2.5, 7.2, -1]
random list 1   :  [0.5, 0.2, 1.4, 4.5, 6.2, -0.5]
random list 2   :  [5.3, 0.3, 0.7, 2.3, 4.2, -0.1]
....
random list 100 :  [0.5, 0.9, 1.1, 2,1, 6.5, -1]

关键是并非所有值都必须更改（例如，在某些情况下，它们可能会喜欢列表 2 中的值）。 有没有一种直接的方法可以在 Python 中实现这一点？

Answer 1

smallest = min(original_list)
largest = max(original_list)

newlist1 = [random.uniform(smallest, largest) for _ in range(len(original_list))]
newlist2 = [random.uniform(smallest, largest) for _ in range(len(original_list))]
# and so on

Answer 2

使用列表理解和numpy.random.uniform ：

import numpy as np

orig = [-1.7683218, 0.22206295, -0.28429198, 5.925369, -3.952484, -3.0728238, 0.09690776, -0.31914753, 3.9695702, 26.934353, 1.4882066, 1.8194668, -0.5614318, 1.2354431, -0.09714768, -0.15579335, -0.059994906, 1.0105655, -23.25607, 31.982368, -0.09390785, 0.17786688, 0.36164832, -4.673975, 13.495866, -3.57134, 0.5583399, -1.801314, 2.4207468, 2.0513844, -3.429592, -9.599998, 23.412394, -3.963623, 6.930485, 2.5186272, 0.6805691, -1.1615586, -0.915736, -2.6307302, -14.409785, 0.6327307, 10.512744, -0.09292421, -0.61977243, 0.35928893, -1.3844814, 8.098062, -0.8270248, 0.47219157, 0.089366496, 0.9056338, 1.5297629, 3.3246832, -0.9748858, 36.62332, -1.0525678, -0.87139374, 6.7600174, 36.210625, -0.25728267, 14.568578, 0.87466383, -4.2237897, -5.4309, 19.762472, 0.8426512, -0.7807278, 0.03435099, 12.787761, -4.9308186, -1.4322343, 0.49790275, -12.979129, 0.18121482, -0.81953144, -1.5393608, 17.757078, 3.5726204, -11.319154, -0.002896044, -1.8806648, 0.30027565, -2.6210017, 16.230186, -2.2566936, 37.37506, -2.7738526, -0.91440165, -3.652771, 1.8378688, -0.25519317, 0.5222581, 0.2189773, 23.825306, 0.3779062, 2.6709516, 0.84001434, -0.41394734, -0.600579, -3.1629875, 0.2880843, -3.9132822, 5.674796, -0.5569526, 0.30253112, -4.4269695, 4.5206604, -0.8477638, 0.0032483074, -2.2814171, 0.5524869, -1.4271426, -0.24263692, 1.0095457, -3.187037, -1.6656531, 1.4805393, 0.064992905, -4.8124804, -0.07194552, -0.28692132, -0.19502515, 0.010771384, -32.744797, 1.2642047, 6.3942785, -1.2971659, 29.70087, 0.19707158, -2.734262, 2.8497686, -1.710305, -1.3836008, 22.758884, -1.8488939, 4.1740856, 0.26019523, -8.814447, -3.937495, 0.22731477, -0.7874651, 17.22002, -7.89242, -0.5795766, 3.3960745, 1.0440702, 0.5483718, 1.2849183, -0.63732344, -40.38428, -4.25527, 3.034935, 0.25527972, -0.81940174, -7.0720696, 1.7420169, 14.904871, -1.5399592, 0.20110837, 0.1902977, 2.5790472, -28.560707, 0.09560776, -0.973604, 0.6214314, -5.1268454, -0.9104073, 33.082394, 0.23800176, -9.696023, 12.288443, -16.52249, -7.6811, -21.928356, 25.690449, -0.6803232, -1.4738222, -1.831514, 0.00013296002, -3.1330614, 3.6067219, -3.0617614, -6.334016, -24.856865, -6.0669985, 2.8829474, 0.76423097, -0.21836776, -2.3173273, -2.092735, -0.19577695, 4.2984896, 0.029742926, 1.0902604, -0.28707412, -0.1671038, -0.4607489, -15.966867, -1.7149612, -1.3445716, 1.400264, 4.906401, -6.314724, -0.92188597, -0.14341217, -6.819194, 1.2750683, 21.634096, 0.5503013, 5.2122655, -0.096101895, -0.69029164, 2.6239898, -26.33101, -3.7901835, 10.026649, 1.0661886, 0.8891293, 34.24628, -0.9036363, -4.4846773, -30.846636, -5.8609247, -0.018534392, 4.657759e-06, 16.96108, 10.725708, -0.3170653, -3.2331817, 0.73887914, 0.69840825, 0.9043666, 1.0727708, 1.6571997, -0.70257163, 2.4863558, 0.07501343, -35.059708, 0.72496796, -3.0723267, -3.2004805, -0.9447444, 0.56954986, 2.6018164, -0.49256825, 22.71359, 0.45523545, -2.1936522, 4.008838, 0.62327665, 10.315046, 1.4006382, 1.1290226, 1.2660133, -8.46607]

a = min(orig)
b = max(orig)
n = len(orig)
res = [[np.random.uniform(a,b,n)] for i in range(100)]

你会得到res ，它是一个包含100列表（大小为len(orig) ）在[min(orig), max(orig))上均匀分布的数字的列表。

Answer 3

下面的代码打印您需要的内容作为输出。 首先，您必须在原始列表中找到最大和最小数字，然后您必须使用随机库和 random.uniform() 函数来获取所需内容。

import random
original_list = [0.5, 0.8, 1.1, 2.5, 7.2, -1]
max_number = max(original_list)
min_number = min(original_list)

'''because you need 100 more lists'''
for i in range(100):
    random_list = []
    for j in range(len(original_list)):
        random_list.append(round(random.uniform(min_number,max_number),1))
    print('random list '+str(i+1)+' ', end='')
    print(random_list)