将JSON转换为CSV，CSV为空

Question

我正在尝试将JSON中的yelps数据集转换为csv格式。 创建的新的csv文件为空。

我尝试了不同的方法来遍历JSON，但是它们都给了我一个零字节的文件。

json文件如下所示：

{"business_id":"1SWheh84yJXfytovILXOAQ","name":"Arizona Biltmore Golf Club","address":"2818 E Camino Acequia Drive","city":"Phoenix","state":"AZ","postal_code":"85016","latitude":33.5221425,"longitude":-112.0184807,"stars":3.0,"review_count":5,"is_open":0,"attributes":{"GoodForKids":"False"},"categories":"Golf, Active Life","hours":null}

import json 
import csv

infile = open("business.json","r")
outfile = open("business2.csv","w")

data = json.load(infile)
infile.close()

out = csv.writer(outfile)

out.writerow(data[0].keys())
for row in data:
    out.writerow(row.values())

代码运行时，我收到一条“额外数据”消息。 新的business2 csv文件为空，大小为零字节。

Answer 1

如果您的JSON只有一行，请尝试

infile = open("business.json","r")
outfile = open("business2.csv","w")

data = json.load(infile)
infile.close()

out = csv.writer(outfile)

#print(data.keys())
out.writerow(data.keys())
out.writerow(data.values())

Answer 2

嗨，请尝试以下代码，使用with命令，当控件移出with范围时，文件访问将自动关闭

infile = open("business.json","r")
outfile = open("business2.csv","w")

data = json.load(infile)
infile.close()
headers = list(data.keys())
values = list(data.values())

with open("business2.csv","w") as outfile:
    out = csv.writer(outfile)
    out.writerow(headers)
    out.writerow(values)

Answer 3

您需要使用with关闭文件。

import json 
import csv

infile = open("business.json","r")


data = json.load(infile)
infile.close()

with open("business2.csv","w") as outfile:
    out = csv.writer(outfile)
    out.writerow(list(data.keys()))
    out.writerow(list(data.values()))