[英]How to open a link in a new tab with Python selenium ChromeDriver
[英]How to open a link in a new tab with python and selenium
我想在新标签页面中打开我在网站上找到的链接。 我试图打开一个新选项卡,并按照此处的建议将链接的URL传递给驱动程序,但是,新选项卡根本无法打开。 (关于如何打开新标签还有其他一些建议,但它们似乎都不适用于我。)
所以我最近的尝试是右键单击链接并按“t”在新选项卡中打开链接,如下所示:
from selenium import webdriver
from selenium.webdriver.common.keys import Keys
from selenium.webdriver.common.action_chains import ActionChains
# Using Firefox to access web
driver = webdriver.Firefox()
# Open the website
driver.get('https://registers.esma.europa.eu/publication/searchRegister?core=esma_registers_firds')
# search for information
elem = driver.find_element_by_id('keywordField')
elem.clear()
elem.send_keys('XS1114155283')
button = driver.find_element_by_id('searchSolrButton')
button.click()
table_body = driver.find_element_by_xpath("//table[@id='T01']/tbody")
for link in table_body.find_elements_by_tag_name('a'):
act = ActionChains(driver)
act.context_click(link)
act.send_keys("t")
act.perform()
# ... do something in the new tab, close tab, and open next link ...
但是,我在act.perform()
上收到一条错误消息
MoveTargetOutOfBoundsException: (974, 695) is out of bounds of viewport width (1366) and height (654)
我通过在新窗口中打开链接来管理工作,但我更喜欢tab-version,因为打开新的浏览器窗口而不是新选项卡需要更长的时间。
您可以使用driver.execute_script()
函数在新选项卡中打开链接
from selenium import webdriver
# Using Firefox to access web
driver = webdriver.Firefox()
# Open the website
driver.get('https://registers.esma.europa.eu/publication/searchRegister?core=esma_registers_firds')
# search for information
elem = driver.find_element_by_id('keywordField')
elem.clear()
elem.send_keys('XS1114155283')
button = driver.find_element_by_id('searchSolrButton')
button.click()
table_body = driver.find_element_by_xpath("//table[@id='T01']/tbody")
for link in table_body.find_elements_by_tag_name('a'):
href = link.get_attribute('href')
# open in new tab
driver.execute_script("window.open('%s', '_blank')" % href)
# Switch to new tab
driver.switch_to.window(driver.window_handles[-1])
# Continuous your code
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