[英]Pass Variable Via JSON with CURL
如何通过JSON将表单变量传递给另一个页面? 我创建了两个php文件,文件名为page_login.php和login.php。 但是,在运行login_post.php时,$ json值无法传递给login.php
page_login.php:
$email = test@gmail.com;
$password = 123;
$json = array('email' => $email, 'password' => hash("sha256",$password));
$json = json_encode($json);
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL,"https://localhost/login.php");
curl_setopt($ch, CURLOPT_POST, 1);
curl_setopt($ch, CURLOPT_POSTFIELDS, $json);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
$server_output = curl_exec($ch);
curl_close ($ch);
login.php中:
$json=json_decode($_REQUEST["json"],true);
print $json;
尝试这个
page_login.php
$email = "test@gmail.com";
$password = "123";
$json = array('email' => $email, 'password' => hash("sha256",$password));
$json = json_encode($json);
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL,"http://localhost/login.php");
curl_setopt($ch, CURLOPT_POST, 1);
curl_setopt($ch, CURLOPT_POSTFIELDS, http_build_query(array("json" => $json)));
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
$server_output = curl_exec($ch);
curl_close ($ch);
echo $server_output;
的login.php
$json=json_decode($_REQUEST["json"],true);
foreach ($json as $key => $value) {
echo $key . ": " . $value;
echo "<BR>";
}
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