通过带有CURL的JSON传递变量

Question

How to pass a form variable to another page via JSON? I had create two php file with file naming page_login.php and login.php. However when running login_post.php, the $json value unable pass to login.php

page_login.php:

$email = test@gmail.com;
$password = 123;

$json = array('email' => $email, 'password' => hash("sha256",$password));
$json = json_encode($json);

$ch = curl_init();      
curl_setopt($ch, CURLOPT_URL,"https://localhost/login.php");
curl_setopt($ch, CURLOPT_POST, 1);
curl_setopt($ch, CURLOPT_POSTFIELDS, $json);                                                                                                           
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);

$server_output = curl_exec($ch);
curl_close ($ch);

login.php:

$json=json_decode($_REQUEST["json"],true);
print $json;

Answer 1

Try this

page_login.php

$email = "test@gmail.com";
$password = "123";

$json = array('email' => $email, 'password' => hash("sha256",$password));
$json = json_encode($json);

$ch = curl_init();      
curl_setopt($ch, CURLOPT_URL,"http://localhost/login.php");
curl_setopt($ch, CURLOPT_POST, 1);
curl_setopt($ch, CURLOPT_POSTFIELDS, http_build_query(array("json" => $json)));                                                                                                           
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);

$server_output = curl_exec($ch);
curl_close ($ch);

echo $server_output;

login.php

$json=json_decode($_REQUEST["json"],true);
foreach ($json as $key => $value) {
    echo $key . ": " . $value;
    echo "<BR>";
}