[英]In SQL how to calculate days in a year based on a start date and the number of days lapsed
如果我有一个开始日期和已经失效的天数,那么计算每年的天数是什么?
例如,日期(ymd)2013-01-01和已过去的天数为1000。
我希望结果看起来像这样
2013 = 365
2014 = 365
2015 = 270
这可以写成像datediff
这样的函数吗?
我尝试过使用日历表,但当然,链接到这只会给我2013 = 1000
我的日历表看起来像这样。
DATE_ID | DATE | CALENDAR_YEAR | FINANCIAL_YEAR
-----------------------------------------------
20130101 | 2013-01-01 | 2013 | 2013/14
这就是我尝试过的。
选择
D.FISCAL_YEAR,SUM([DAYS])AS NUMBER_OF_DAYS
来自[dbo]。[FACT] F.
LEFT JOIN [dbo]。[DIM_DATE] D ON D.DATE_ID = F.DATE_ID
通过...分组
D.FISCAL_YEAR
结果是。
FISCAL_YEAR | NUMBER_OF_DAYS
----------------------------
2013/14 |2820
2014/15 |6635
2015/16 |2409
我个人会建立一个计数表来做到这一点。 构建完成后,您可以轻松获取每个日期并计算每年的天数:
DECLARE @YMD date = '20130101',
@Lapsed int = 1000;
--Build a Tally table
WITH N AS(
SELECT N
FROM (VALUES(NULL),(NULL),(NULL),(NULL),(NULL),(NULL),(NULL),(NULL),(NULL),(NULL)) N(N)),
Tally AS(
SELECT ROW_NUMBER() OVER (ORDER BY (SELECT NULL)) -1 AS I
FROM N N1, N N2, N N3, N N4), --10,000 should be enough
--Build the dates table
Dates AS(
SELECT DATEADD(DAY, T.I, @YMD) AS CalendarDate
FROM Tally T
WHERE T.I <= @Lapsed - 1)
--And count the days
SELECT DATEPART(YEAR, CalendarDate) AS Year,
COUNT(CalendarDate) AS Days
FROM Dates D
GROUP BY DATEPART(YEAR, CalendarDate);
作为一个功能:
CREATE FUNCTION CountDays (@YMD date, @Lapsed int)
RETURNS table
AS RETURN
--Build a Tally table
WITH N AS(
SELECT N
FROM (VALUES(NULL),(NULL),(NULL),(NULL),(NULL),(NULL),(NULL),(NULL),(NULL),(NULL)) N(N)),
Tally AS(
SELECT ROW_NUMBER() OVER (ORDER BY (SELECT NULL)) -1 AS I
FROM N N1, N N2, N N3, N N4), --10,000 should be enough
--Build the dates table
Dates AS(
SELECT DATEADD(DAY, T.I, @YMD) AS CalendarDate
FROM Tally T
WHERE T.I <= @Lapsed - 1)
--And count the days
SELECT DATEPART(YEAR, CalendarDate) AS Year,
COUNT(CalendarDate) AS Days
FROM Dates D
GROUP BY DATEPART(YEAR, CalendarDate);
GO
SELECT *
FROM (VALUES('20130101',1000),
('20150501',755))V(YMD, Lapsed)
CROSS APPLY dbo.CountDays(V.YMD,V.Lapsed) CD;
一种方法是递归CTE:
with dates as (
select v.d, 1000 - datediff(day, v.d, dateadd(year, 1, v.d)) as days
from (values (datefromparts(2013, 1, 1))) v(d)
union all
select dateadd(year, 1, d), days - datediff(day, d, dateadd(year, 1, d))
from dates
where days > 0
)
select d,
(case when days > 0 then datediff(day, d, dateadd(year, 1, d))
else datediff(day, d, dateadd(year, 1, d)) + days
end)
from dates;
这是一个db <>小提琴。
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