[英]How Do you prevent overwriting of data in a Dictionary through a for loop
[英]How do you return a dictionary through a function?
我试图通过使用jupyter笔记本的代码中显示的函数返回字典。 我是Python的初学者,不知道如何去做,但我觉得答案是微不足道的。在我运行它的代码中,我得到{}。
我不确定是否需要for循环或if语句。
def build_book_dict(titles, pages, firsts, lasts, locations):
if True:
return dict()
else:
None
titles = ["Harry Potter", "Fear and Lothing in Las Vegas"]
pages = [200, 350]
firsts = ["J.K.", "Hunter"]
lasts = ["Rowling", "Thompson"]
locations = ["NYC", "Aspen"]
book_dict = build_book_dict(titles, pages, firsts, lasts, locations)
print (book_dict)
result should be -->
{'Fear and Lothing in Las Vegas': {'Publisher': {'Location': 'Aspen'},
'Author': {'Last': 'Thompson', 'First': 'Hunter'}, 'Pages': 350},
'Harry Potter': {'Publisher': {'Location': 'NYC'},
'Author': {'Last': 'Rowling', 'First': 'J.K.'}, 'Pages': 200}}
这是一个可能的解决方案:
小心! 所有列表必须大小相同!
def build_book_dict(titles, pages, firsts, lasts, locations):
dict = {}
try:
for i in range(len(titles)):
dict[titles[i]] = {'Publisher':{'Location':locations[i]},
'Author':{'Last':lasts[i], 'First':firsts[i]}}
return dict
except Exception as e:
print('Invalid length', e)
titles = ["Harry Potter", "Fear and Lothing in Las Vegas"]
pages = [200, 350]
firsts = ["J.K.", "Hunter"]
lasts = ["Rowling", "Thompson"]
locations = ["NYC", "Aspen"]
book_dict = build_book_dict(titles, pages, firsts, lasts, locations)
print (book_dict)
字典不会自动组装并知道您想要的格式。 由于您从一个独立的列表开始,您可以将它们zip
成组以轻松地迭代它们并构建您的字典:
def build_book_dict(*args):
d = dict()
for title, page, first, last, location in zip(*args):
d[title] = {"Publisher": {"Location":location},
"Author": {"last": last, "first":first},
"Pages": page}
return d
titles = ["Harry Potter", "Fear and Lothing in Las Vegas"]
pages = [200, 350]
firsts = ["J.K.", "Hunter"]
lasts = ["Rowling", "Thompson"]
locations = ["NYC", "Aspen"]
book_dict = build_book_dict(titles, pages, firsts, lasts, locations)
from pprint import pprint # pretty print
pprint(book_dict)
结果
{'Fear and Lothing in Las Vegas': {'Author': {'first': 'Hunter',
'last': 'Thompson'},
'Pages': 350,
'Publisher': {'Location': 'Aspen'}},
'Harry Potter': {'Author': {'first': 'J.K.', 'last': 'Rowling'},
'Pages': 200,
'Publisher': {'Location': 'NYC'}}}
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