[英]Haskell: Question about Partial Application
我正在阅读“为了大好而学习你的哈斯克尔!”这本书。 由Miran Lipovaca撰写并在第5章中学习高阶函数。
其中一个示例涉及以下功能:
applyTwice :: (a -> a) -> a -> a
applyTwice f x = f (f x)
以下是函数输出的示例:
ghci> applyTwice (++ " HAHA") "HEY"
"HEY HAHA HAHA"
ghci> applyTwice ("HAHA " ++) "HEY"
"HAHA HAHA HEY"
对于第一个示例,我理解字符串是通过以下方式使用串联运算符生成的:
"HEY" ++ " HAHA"
"HEY HAHA" ++ " HAHA"
"HEY HAHA HAHA"
但是,我不明白连接运算符在第二个示例中是如何工作的。 输出字符串“HAHA HAHA HEY”是如何产生的? 任何见解都表示赞赏。
对于第一个示例,我理解字符串是通过以下方式使用串联运算符生成的:
"HEY" ++ " HAHA" "HEY HAHA" ++ " HAHA" "HEY HAHA HAHA"
而不是直接跳转到中缀表达式(即++
介于其间),如果您根据函数进行思考,它会有所帮助。
(++ " HAHA") :: [Char] -> [Char] -- #1 this is a function (++ is partially applied)
"HEY" :: [Char]
(++ " HAHA") "HEY" -- apply "HEY" as an argument to #1
-- same as "HEY" ++ " HAHA"
(+) :: (Num a) => a -> a -> a -- #2 a binary function
(+) 1 2 -- #3 apply 1 and 2 as arguments to #2
-- same as 1 + 2
-- technically, #3 is curried as
-- ((+) 1) 2 -- i.e. (+) 1 is a partially applied function, which is then applied to 2
如果你将(++ " HAHA")
替换为applyTwice
的定义,你就得到了
applyTwice f x = f (f x)
applyTwice (++ " HAHA") "HEY" = (++ " HAHA") ((++ " HAHA") "HEY")
= (++ " HAHA") ("HEY" ++ " HAHA")
= (++ " HAHA") ("HEY HAHA")
= "HEY HAHA" ++ " HAHA"
= "HEY HAHA HAHA"
现在使用applyTwice ("HAHA " ++) "HEY"
。
applyTwice f x = f (f x)
applyTwice ("HAHA " ++) "HEY" = ("HAHA " ++) (("HAHA " ++) "HEY")
= ("HAHA " ++) ("HAHA " ++ "HEY")
= ("HAHA " ++) ("HAHA HEY")
= "HAHA " ++ "HAHA HEY"
= "HAHA HAHA HEY"
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