[英]Using ramda to modify a property in array of Objects
我正在尝试使用ramda
从对象数组中删除一些属性。 我有一系列要删除的属性:
const colToHide = ['name', 'age'];
// those properties are selected by the user
我想从一组对象中删除属性'name'
和'age'
(或任何用户选择的属性)。 对象数组是这样的:
const person = [
{name:'sam', age:'24', address:'xyz avenue', employed:true},
{name:'john', age:'25', address:'xyz avenue', employed:true}
];
什么是更新对象数组的正确方法?
您可以将.omit()方法与.map()结合使用。 像这样:
const person = [ {name:'sam', age:'24', address:'xyz avenue', employed:true}, {name:'john', age:'25', address:'xyz avenue', employed:true} ] const omitKeys = (keys, arr) => R.map(R.omit(keys), arr); console.log(omitKeys(["name", "age"], person));
.as-console {background-color:black !important; color:lime;} .as-console-wrapper {max-height:100% !important; top:0;}
<script src="//cdnjs.cloudflare.com/ajax/libs/ramda/0.25.0/ramda.min.js"></script>
甚至,您可以将.compose()用作对评论进行建议的@ScottSauyet来执行:
const omitKeys = R.compose(R.map, R.omit);
然后将其用作:
omitKeys(["name", "age"])(person);
const person = [ {name:'sam', age:'24', address:'xyz avenue', employed:true}, {name:'john', age:'25', address:'xyz avenue', employed:true} ] const omitKeys = R.compose(R.map, R.omit); console.log(omitKeys(["name", "age"])(person));
.as-console {background-color:black !important; color:lime;} .as-console-wrapper {max-height:100% !important; top:0;}
<script src="//cdnjs.cloudflare.com/ajax/libs/ramda/0.25.0/ramda.min.js"></script>
或使用R.useWith
无点样式:
const omit = R.useWith(R.map, [ R.omit, R.identity, ]); const persons = [ {name:'sam', age:'24', address:'xyz avenue', employed:true}, {name:'john', age:'25', address:'xyz avenue', employed:true} ] console.log( 'result', omit(["name", "age"], persons), );
<script src="//cdnjs.cloudflare.com/ajax/libs/ramda/0.25.0/ramda.min.js"></script>
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