使用ramda修改對象數組中的屬性

Question

我正在嘗試使用ramda從對象數組中刪除一些屬性。 我有一系列要刪除的屬性：

const colToHide = ['name', 'age']; 
// those properties are selected by the user 

我想從一組對象中刪除屬性'name'和'age' （或任何用戶選擇的屬性）。 對象數組是這樣的：

const person = [
  {name:'sam', age:'24', address:'xyz avenue', employed:true},
  {name:'john', age:'25', address:'xyz avenue', employed:true}
];

什么是更新對象數組的正確方法？

Answer 1

您可以將.omit（）方法與.map（）結合使用。 像這樣：

 const person = [ {name:'sam', age:'24', address:'xyz avenue', employed:true}, {name:'john', age:'25', address:'xyz avenue', employed:true} ] const omitKeys = (keys, arr) => R.map(R.omit(keys), arr); console.log(omitKeys(["name", "age"], person)); 

 .as-console {background-color:black !important; color:lime;} .as-console-wrapper {max-height:100% !important; top:0;} 

 <script src="//cdnjs.cloudflare.com/ajax/libs/ramda/0.25.0/ramda.min.js"></script> 

甚至，您可以將.compose（）用作對評論進行建議的@ScottSauyet來執行：

const omitKeys = R.compose(R.map, R.omit);

然后將其用作：

omitKeys(["name", "age"])(person);

 const person = [ {name:'sam', age:'24', address:'xyz avenue', employed:true}, {name:'john', age:'25', address:'xyz avenue', employed:true} ] const omitKeys = R.compose(R.map, R.omit); console.log(omitKeys(["name", "age"])(person)); 

 .as-console {background-color:black !important; color:lime;} .as-console-wrapper {max-height:100% !important; top:0;} 

 <script src="//cdnjs.cloudflare.com/ajax/libs/ramda/0.25.0/ramda.min.js"></script> 

Answer 2

或使用R.useWith無點樣式：

 const omit = R.useWith(R.map, [ R.omit, R.identity, ]); const persons = [ {name:'sam', age:'24', address:'xyz avenue', employed:true}, {name:'john', age:'25', address:'xyz avenue', employed:true} ] console.log( 'result', omit(["name", "age"], persons), ); 

 <script src="//cdnjs.cloudflare.com/ajax/libs/ramda/0.25.0/ramda.min.js"></script>