[英]How to query records where one field greater than another by x days?
我有一张像这样的桌子:
+----+------------+------------+
| id | expiry | timestamp |
+----+------------+------------+
| 1 | 2018-11-29 | 2018-11-01 |
| 2 | 2018-12-27 | 2018-11-01 |
| 3 | 2019-01-31 | 2018-11-01 |
| 4 | 2018-11-29 | 2018-11-01 |
| 5 | 2018-12-27 | 2018-11-01 |
+----+------------+------------+
我如何可以查询所有记录,其expiry
是从不到30天timestamp
? 即
timestamp + 30 days > expiry
我建议:
where expiry < timestamp + interval 30 day
你可以试试这个
SELECT * FROM table_name WHERE DATE_ADD(TIMESTAMP , INTERVAL 30 DAY) > expiry;
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