我需要计算每个员工每月的平均产量

Question

我需要创建一个报告，显示平均每天至少生产30件的员工

我有2张桌子：

Employees: id, name, surname
Production: id, date_time, id_employee, [..], quantity_produced

员工表中的id =生产表中的id_employee

---

SELECT name, surname, Avg(quantity_produced), Month(data_ora) Mnth
FROM production inner join employees on employees.id = production.id_employee
GROUP BY name, quantity_produced, Month(date_time);

要么

select name, surname, quantity_produced, avg(quantity_produced) as avgentrypermonth 
    from (
select month(date_time) as month ,count(1) as quantity
     group by month(date_time));

要么

select name, surname, quantity_produced
    from production 
     inner join employees on employees.id = production.id_employee
    where avg(quantity_produced) > 30;

Answer 1

我最有可能在以下查询中取消一项。

但是，如果没有示例数据和预期结果，很难提出可靠的建议。

查询：

SELECT 
    Production.id_employee,
    AVG(Production.quantity_produced)
FROM 
    Production
WHERE
    Production.date_time BETWEEN
                         (LAST_DAY(NOW()) + INTERVAL 1 DAY) - INTERVAL 1 MONTH # first day of current month
                         AND
                         LAST_DAY(NOW()) # last day of current month
GROUP BY 
    Production.id_employee

查询何时需要员工记录：

SELECT 
    Employees.name,
    Employees.surname,
    AVG(Production.quantity_produced)
FROM 
    Production
INNER JOIN 
    Employees ON Production.id_employee = Employees.id
WHERE
    Production.date_time BETWEEN
                         (LAST_DAY(NOW()) + INTERVAL 1 DAY) - INTERVAL 1 MONTH  # first day of current month
                         AND
                         LAST_DAY(NOW()) # last day of current month
GROUP BY 
    Employees.id

请注意，以上查询至少假设了MySQL 5.7.5+和SQL 1999+标准的可选功能，即功能依赖 。

见手册

或作为相关子查询：正确建立索引后应该可以

SELECT 
    (SELECT Employees.name FROM Employees.id = Production.id_employee) AS name,
    (SELECT Employees.surname FROM Employees.id = Production.id_employee) AS surname,
    AVG(Production.quantity_produced)
FROM 
    Production
WHERE
    Production.date_time BETWEEN
                         (LAST_DAY(NOW()) + INTERVAL 1 DAY) - INTERVAL 1 MONTH # first day of current month
                         AND LAST_DAY(NOW()) # last day of current month
GROUP BY 
    Production.id_employee

Answer 2

对于过滤器聚合结果，您需要具有子句

SELECT name, surname, Avg(quantity_produced), Month(date_time) Mnth
FROM production 
inner join employees on employees.id = production.id_employee
GROUP BY name, surname, Month(date_time)
having Avg(quantity_produced) > 30 ;

以及年份

SELECT name, surname, Avg(quantity_produced), Month(date_time) Mnth, year(date_time) year
FROM production 
inner join employees on employees.id = production.id_employee
GROUP BY name, surname, Month(date_time), year(date_time) year
having Avg(quantity_produced) > 30 ;

Answer 3

在使用几个月时，您应该确保也考虑到了这一年：

SELECT year(p.data_ora) as yyyy, month(p.data_ora) as mm,
       e.name, e.surname, avg(p.quantity_produced),
FROM production p inner join
     employees e
     on e.id = p.id_employee
GROUP BY year(p.data_ora), month(p.data_ora,
         e.name, e.surname
HAVING avg(p.quantity_produced) >= 30
ORDER BY year(p.data_ora), month(p.data_ora),
         e.name, e.surname;

假设production具有员工每天工作的产量。

笔记：

• 当表引用多个表时，请限定所有列引用。
• 使用表别名，以便查询更易于编写和阅读。
• 记住那一年！ （当您工作数月时）

Answer 4

    I think this should work , can you please try it once. And may be little modification required, Comment here I will try to do the fixes.
  1.Select
         E.id "Employee ID",
         E.name "Employee Name",
         Month(P.date_time) "Month",
         AVG(P.quantity_produced) "Quantity Produced"
    From Employee as E
         Join Production as P on E.id=P. id_employee
    Group by
         E.id,E.name,Month(P.date_time)
    Having Avg(P.quantity_produced) > 30

2.Select
         E.name "Employee Name",
         Month(P.date_time) "Month",
         AVG(P.quantity_produced) "Quantity Produced"
    From Employee as E
         Join Production as P on E.id=P. id_employee
    Group by
         E.name,Month(P.date_time)
    Having Avg(P.quantity_produced) > 30