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Scrapy-请求有效载荷格式和类型

[英]Scrapy - Request Payload format and types

这是我的抓取过程的起点。

https://www.storiaimoveis.com.br/alugar/brasil

这是AJAX调用,它以JSON格式返回每个页面的数据。

https://www.storiaimoveis.com.br/api/search?fields=%24%24meta.geo.postalCodeAddress.city%2C%24%24meta.geo.postalCodeAddress.neighborhood%2C%24%24meta.geo.postalCodeAddress .street%2C%24%24meta.location%2C%24%24meta.created%2Caddress.number%2Caddress.postalCode%2Caddress.neighborhood%2Caddress.state%2Cmedia%2ClivingArea%2CtotalArea%2Ctypes%2Coperation%2CsalePrice%2CrentPrice%2CnewDevelopment %2CadministrationFee%2CyearlyTax%2Caccount.logoUrl%2Caccount.name%2Caccount.id%2Caccount.creci%2Cgarage%2Cbedrooms%2Csuites%2Cbathrooms%2Cref&optimizeMedia =真大小= 20&从= 0&的sessionId = 5ff29d7e-88d0-54d5-2641-e203cafd6f4e

我的POST请求失败,错误404。这些请求需要有效负载,这给我带来了麻烦。 我总是以某种方式解决问题,但现在我想了解我对他们的错。

我的问题是;

  • 与刮擦请求一起发送的请求有效载荷是否需要特定的类型或格式?
  • 我需要在发送它们之前将其调用json.dumps(payload)还是将其作为字典发送?
  • 发送有效负载之前,我是否需要将每个key:value对都转换为字符串?
  • 是我的请求失败的其他原因吗?

这是我的代码的相关部分。

class MySpider(CrawlSpider):

    name = 'myspider'

    start_urls = [
        'https://www.storiaimoveis.com.br/api/search?fields=%24%24meta.geo.postalCodeAddress.city%2C%24%24meta.geo.postalCodeAddress.neighborhood%2C%24%24meta.geo.postalCodeAddress.street%2C%24%24meta.location%2C%24%24meta.created%2Caddress.number%2Caddress.postalCode%2Caddress.neighborhood%2Caddress.state%2Cmedia%2ClivingArea%2CtotalArea%2Ctypes%2Coperation%2CsalePrice%2CrentPrice%2CnewDevelopment%2CadministrationFee%2CyearlyTax%2Caccount.logoUrl%2Caccount.name%2Caccount.id%2Caccount.creci%2Cgarage%2Cbedrooms%2Csuites%2Cbathrooms%2Cref&optimizeMedia=true&size=20&from=0&sessionId=5ff29d7e-88d0-54d5-2641-e203cafd6f4e'
    ]

    page = 1
    payload = {"locations":[{"geo":{"top_left":{"lat":5.2717863,
                                                "lon":-73.982817},
                                    "bottom_right":{"lat":-34.0891,
                                                    "lon":-28.650543}},
                             "placeId":"ChIJzyjM68dZnAARYz4p8gYVWik",
                             "keywords":"Brasil",
                             "address":{"label":"Brasil","country":"BR"}}],
               "operation":["RENT"],
               "bathrooms":[],
               "bedrooms":[],
               "garage":[],
               "features":[]}
    headers = {
        'Accept': 'application/json',
        'Content-Type': 'application/json',
        'Referer': 'https://www.storiaimoveis.com.br/alugar/brasil',
        'User-Agent': 'Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/75.0.3770.100 Safari/537.36'
    }


    def parse(self, response):
        for url in self.start_urls:
            yield scrapy.Request(url=url,
                                 method='POST',
                                 headers=self.headers,
                                 body=json.dumps(self.payload),
                                 callback=self.parse_items)

    def parse_items(self, response):
        from scrapy.shell import inspect_response
        inspect_response(response, self)
        print response.text

是的,您需要调用json.dumps(payload)因为请求主体需要按文档中所述以str or unicode表示: https : //docs.scrapy.org/en/latest/topics/request-response.html#请求的对象

但是,在您的情况下,由于缺少这两个标头,您的请求失败: Content-TypeReferer

为了获得正确的请求标头,我通常要做的是:

  1. 检查Chrome开发工具中的标题:

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  1. 使用curlPostman发出请求,直到获得正确的标题为止。 在这种情况下, Content-TypeReferer似乎足以满足HTTP 200响应状态:

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