通过在javascript中传递键和值来从数组中获取对象

Question

这是我的对象数组。 我想通过在函数中传递查询来过滤对象。

const products = [{
    name: "A",
    color: "Blue",
    size: 50
  },
  {
    name: "B",
    color: "Blue",
    size: 60
  },
  {
    name: "C",
    color: "Black",
    size: 70
  },
  {
    name: "D",
    color: "Green",
    size: 50
  }
];

我想要的输出将从我在函数中传递的查询中过滤，该函数可以是任何东西

{
  name: "A",
  color: "Blue",
  size: 50
}, {
  name: "C",
  color: "Black",
  size: 70
}

这是我将传递给函数的查询对象

const filter = {
  color: ["Blue", "Black"],
  size: [70, 50]
};

这是我的函数，我可以将其分配给其他变量并将其用于进一步的操作

const filteredData = filterIt(products, filter);

Answer 1

您可以获取过滤器对象的条目并获取用于检查includes键和值。

 const filterBy = filter => o => Object.entries(filter).every(([k, v]) => v.includes(o[k])), filterIt = (array, filter) => array.filter(filterBy(filter)), products = [{ name: "A", color: "Blue", size: 50 }, { name: "B", color: "Blue", size: 60 }, { name: "C", color: "Black", size: 70 }, { name: "D", color: "Green", size: 50 }], filter = { color: ["Blue", "Black"], size: [70, 50] }, filteredData = filterIt(products, filter); console.log(filteredData);

 .as-console-wrapper { max-height: 100% !important; top: 0; }

Answer 2

这是另一种选择：

function filterIt(products, filter) {
  return products.filter(p => {
    for (const k in filter) {
      if (filter[k].indexOf(p[k]) === -1) {
        return false;
      }
    }
    return true;
  })
}

观看演示

如果您想在逻辑中使用 OR 而不是 AND ，则先前修改的函数将是：

function filterIt(products, filter) {
  return products.filter(p => {
    for (const k in filter) {
      // if a value of any property of the product is contained in a filter array, include it
      if (filter[k].indexOf(p[k]) !== -1) {
        return true;
      }
    }
    return false;
  })
}

也可以看看这个Demo :)

Answer 3

 const products = [{ name: "A", color: "Blue", size: 50 }, { name: "B", color: "Blue", size: 60 }, { name: "C", color: "Black", size: 70 }, { name: "D", color: "Green", size: 50 } ]; const filter = { color: ["Blue", "Black"], size: [70, 50] }; let filterIt = (products, filter) => { return products.filter(p => { //get all filter keys let keys = Object.keys(filter); let validkeys = []; keys.forEach(k=>{ // check if filter property exist and includes filter value if(p.hasOwnProperty(k) && filter[k].includes(p[k])){ validkeys.push(true); } }) //check all filter matches return validkeys.length === keys.length; }); } const filteredData = filterIt(products, filter); console.log("...filteredData", filteredData);