Fetching Objects from Array by passing key & value in javascript

Question

This is my Array of objects. I want to filter the objects by passing query in a function.

const products = [{
    name: "A",
    color: "Blue",
    size: 50
  },
  {
    name: "B",
    color: "Blue",
    size: 60
  },
  {
    name: "C",
    color: "Black",
    size: 70
  },
  {
    name: "D",
    color: "Green",
    size: 50
  }
];

My desired output which will filter from the query which I am passing in function which can be anything

{
  name: "A",
  color: "Blue",
  size: 50
}, {
  name: "C",
  color: "Black",
  size: 70
}

This is my query object which I will pass to function

const filter = {
  color: ["Blue", "Black"],
  size: [70, 50]
};

This is my function which I can assign to other variable and use it for further operations

const filteredData = filterIt(products, filter);

Answer 1

You could get the entries of the filter object and take key and value for checking with includes .

 const filterBy = filter => o => Object.entries(filter).every(([k, v]) => v.includes(o[k])), filterIt = (array, filter) => array.filter(filterBy(filter)), products = [{ name: "A", color: "Blue", size: 50 }, { name: "B", color: "Blue", size: 60 }, { name: "C", color: "Black", size: 70 }, { name: "D", color: "Green", size: 50 }], filter = { color: ["Blue", "Black"], size: [70, 50] }, filteredData = filterIt(products, filter); console.log(filteredData);

 .as-console-wrapper { max-height: 100% !important; top: 0; }

Answer 2

Here is another option:

function filterIt(products, filter) {
  return products.filter(p => {
    for (const k in filter) {
      if (filter[k].indexOf(p[k]) === -1) {
        return false;
      }
    }
    return true;
  })
}

See a Demo

If you want to make an OR instead of an AND in the logic the previous function modified would be:

function filterIt(products, filter) {
  return products.filter(p => {
    for (const k in filter) {
      // if a value of any property of the product is contained in a filter array, include it
      if (filter[k].indexOf(p[k]) !== -1) {
        return true;
      }
    }
    return false;
  })
}

See a Demo for this one too :)

Answer 3

 const products = [{ name: "A", color: "Blue", size: 50 }, { name: "B", color: "Blue", size: 60 }, { name: "C", color: "Black", size: 70 }, { name: "D", color: "Green", size: 50 } ]; const filter = { color: ["Blue", "Black"], size: [70, 50] }; let filterIt = (products, filter) => { return products.filter(p => { //get all filter keys let keys = Object.keys(filter); let validkeys = []; keys.forEach(k=>{ // check if filter property exist and includes filter value if(p.hasOwnProperty(k) && filter[k].includes(p[k])){ validkeys.push(true); } }) //check all filter matches return validkeys.length === keys.length; }); } const filteredData = filterIt(products, filter); console.log("...filteredData", filteredData);