如何获取包含值的Sqlite3列名？

Question

我有一个sqlite3表，其中包含0和1。我想获取值为1的列名称。我尝试了description和pragma方法，由于某种原因，结果不正确。

以下是我的尝试：

。去污

allResults = c.execute("SELECT * FROM db_1.hope5 WHERE Vehicle = '{}'".format(veh))
all_columnNames = [tup[0] for tup in allResults.description]
inputs_columnNames = all_columnNames[9:]
inputcheck = [tup[9:] for tup in allResults.fetchall()]
inputSelected = [val for i, val in enumerate(inputs_columnNames) if inputcheck[0][i] == 1]

语用

c = connection.cursor()
        c.execute("PRAGMA TABLE_INFO(hope5)")
        names = [tup[1] for tup in c.fetchall()]
        names = names[2:]
        result = c.execute("SELECT * FROM hope5 WHERE Vehicle = '{}' ".format(veh))
        result = result.fetchall()
        test = [names[index] for index, val in enumerate(result[0][2:]) if val==1]

桌子的形状

+----+-----+-----+-----+-----+-----+
| A  |  B  |  C  |  D  |  E  |  F  |
+----+-----+-----+-----+-----+-----+
| 0  |  0  |  1  |  0  | 0   |  1  |
|----|-----|-----|-----|-----|-----|
| 1  |  0  |  0  |  0  | 1   |  0  |
+----+-----+-----+-----+-----+-----+

根据我上面的代码，结果需要为：

test = [A,C,E,F]

Answer 1

所以问题是：

inputSelected = [val for i, val in enumerate(inputs_columnNames) if inputcheck[0][i] == 1]

其中inputcheck [0]应该是j。 通过更改为以下内容，它可以工作：

inputSelected_append = []
for j in range(len(inputcheck)):
    inputSelected = [val for i, val in enumerate(inputs_columnNames) if inputcheck[j][i] == 1]
    inputSelected_append.append(inputSelected)