验证以 .services 结尾的电子邮件地址的 Java 正则表达式

Question

使用java.util.regex.Matcher验证电子邮件地址的正则表达式失败。 它会抛出无效的电子邮件地址或错误。

我将如何修改模式以允许以 .services 结尾的电子邮件地址

import java.util.regex.Matcher;
import java.util.regex.Pattern;

String emailAddress = myemail@something.services;

public static Pattern EMAIL_PATTERN = Pattern.compile(
    "^[_A-Za-z0-9-]+(\\.[_A-Za-z0-9-]+)*@[A-Za-z0-9]+(\\.[A-Za-z0-9]+)*(\\.[A-Za-z]{2,})$");

Matcher matcher = ADDR_PATTERN.matcher(emailAddress);



import java.util.regex.Matcher;
import java.util.regex.Pattern;

String emailAddress = myemail@something.services;

public static Pattern EMAIL_PATTERN = Pattern.compile(
    "^[_A-Za-z0-9-]+(\\.[_A-Za-z0-9-]+)*@[A-Za-z0-9]+(\\.[A-Za-z0-9]+)*(\\.[A-Za-z]{2,})$");

Matcher matcher = ADDR_PATTERN.matcher(emailAddress);

Answer 1

您应该使用“内置” javax.mail.internet.InternetAddress格式验证器，而不是使用正则表达式。 随着您添加其他规则，正则表达式变得更加复杂，而对后缀的基本验证和严格验证是人类可读的。

public static boolean isValidEmailAddress(String email) {
    try {
        InternetAddress emailAddr = new InternetAddress(email);
        emailAddr.validate(); //validates email format

        return true;
    } catch (AddressException ex) {
        return false;
    }
}

Answer 2

^[A-Z0-9._%+-]+@[A-Z0-9.-]+\\.services$

Pattern pattern = Pattern.compile("^[A-Z0-9._%+-]+@[A-Z0-9.-]+\\.services$", Pattern.CASE_INSENSITIVE);
    Matcher matcher = pattern.matcher("myemail@something.services");
    System.out.println("result: "+matcher.find());

基于Java 正则表达式电子邮件