[英]How can I generate a list of arguments unacceptable to getopts in Bash?
[英]How can I take multiple arguments in bash using getopts?
我是第一次使用getopts。 我试图接受2个参数: startyear
和endyear
,脚本将根据这些参数继续进行大量计算。 但是我无法完成这项工作。
我在回声变量方面空白。 我究竟做错了什么?
!/bin/bash
while getopts 'hse:' OPTION; do
case "$OPTION" in
h)
echo "h stands for h"
;;
s)
startyear="$OPTARG"
echo "The value provided is $OPTARG"
;;
e)
endyear="$OPTARG"
echo "The value provided is $OPTARG"
;;
?)
echo "script usage: $(basename $0) [-l] [-h] [-a somevalue]" >&2
exit 1
;;
esac
done
shift "$(($OPTIND -1))"
echo "The value provided is $startyear and $endyear"
根据Gordon Davisson的建议进行了更新。
您需要在s和e后面都包含“:”,以表示这些选项需要参数。
#!/bin/bash
function help() {
# print the help to stderr
echo "$(basename $0) -h -s startyear -e endyear" 2>&1
exit 1
}
# Stop script if no arguments are present
if (($# == 0))
then
help
fi
while getopts 'hs:e:' OPTION; do
case "$OPTION" in
h)
help
;;
s)
startyear="$OPTARG"
;;
e)
endyear="$OPTARG"
;;
esac
done
shift "$(($OPTIND -1))"
# Checking if the startyear and endyear are 4 digits
if [[ ! ${startyear} =~ ^[0-9]{4,4}$ ]] || [[ ! ${endyear} =~ ^[0-9]{4,4}$ ]]
then
echo "Error: invalid year" 2>&1
help
fi
echo "The value provided is $startyear and $endyear"
我的测试运行以上。
$ ./geto -s 2018 -e 2020
The value provided is 2018
The value provided is 2020
The value provided is 2018 and 2020
$
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