查找列表项，然后获取下一个列表项

Question

尝试在列表中找到一个项目，然后获取下一个列表项目

我尝试了迭代器，即枚举器函数。 没有骰子。

lst = ['SOME TEXT FOR THE FIRST ITEM','THE COURT FINDS THAT A COMMUNITY CONTROL SANCTION WILL ADEQUATELY PROTECT THE PUBLIC AND WILL NOT DEMEAN THE SERIOUSNESS OF THE OFFENSE.', 'IT IS THEREFORE ORDERED THAT THE DEFENDANT IS SENTENCED TO 2 YEAR(S) OF COMMUNITY CONTROL, UNDER SUPERVISION OF THE ADULT PROBATION DEPARTMENT WITH THE FOLLOWING CONDITIONS: DEFENDANT TO ABIDE BY THE RULES AND REGULATIONS OF THE PROBATION DEPARTMENT.', 'LAST ITEM IN THE LIST']




for x in lst:
    lst_item = iter(lst)
    if "WILL ADEQUATELY PROTECT" in x:
        print(next(lst_item))

期望得到包含所搜索字符串的项目之后的下一个列表项目。

Answer 1

enumerate函数应该起作用：

for index, item in enumerate(lst):
    if "WILL ADEQUATELY PROTECT" in item:
        print(lst[index + 1])

代码的问题在于，您在整个列表上调用iter，而不是在所需项目之后的列表上调用iter。 如果要使用iter方法，可以执行以下操作：

it = iter(lst)
for item in it:
    if "WILL ADEQUATELY PROTECT" in item:
        print(next(it))

Answer 2

最直接的方法是：

for i in range(len(lst)):
    if "WILL ADEQUATELY PROTECT" in lst[i] and i < len(lst) - 1:
        print(lst[i+1])