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Question

运行代码时，它会按计划要求输入，但未定义列表 alpha。

首先输入没有读取，所以我更改了缩进，但是没有解决定义问题。

def newclassification1(alpha,bravo):
        alpha = ["Jacob", "Jane", "Jim"]
        bravo = ["Male", "Female", "Unknown"]

    name = input("What is the persons name?")
    if name in alpha:
        while True:
            print(bravo[alpha.index(name)])
    else:
        print("The persons name is not in the register.")

错误信息：

Traceback（最近一次调用最后一次）：文件“”，第 7 行，在 NameError：名称 'alpha' 未定义

Answer 1

我做了一些调整，主要是从 function 中删除 alpha 和 bravo。

alpha = ["Jacob", "Jane", "Jim"]
bravo = ["Male", "Female", "Unknown"]
def newclassification1(alpha,bravo):
    name = input("What is the persons name?")
    if name in alpha:
        print(bravo[alpha.index(name)])
    else:
        print("The persons name is not in the register.")
newclassification1(alpha,bravo)

这是可行的，因为由于您将 alpha 和 bravo 传递给 function，因此这些变量应该在 function 之外定义。 此外，我将您的while更改为if ，否则您将获得无限的输出。 Output 为 function 我正在分享：

What is the persons name?Jim
Unknown
What is the persons name?Jane
Female
What is the persons name?a
The persons name is not in the register.

给定 OP 注释：必须在函数中定义alpha和bravo 。

def newclassification1(alpha = [],bravo = []):
    alpha = ["Jacob", "Jane", "Jim"]
    bravo = ["Male", "Female", "Unknown"]
    name = input("What is the persons name?")
    if name in alpha:
        print(bravo[alpha.index(name)])
    else:
        print("The persons name is not in the register.")
newclassification1()

Output：

What is the persons name?Jim
Unknown
What is the persons name?Tim
The persons name is not in the register.
What is the persons name?Jane
Female

Answer 2

我不知道您的最终目的，但这两个代码在Python3上没有任何错误。

第一个：

def newclassification1(alpha,bravo):
    name = input("What is the persons name?")
    if name in alpha:
        while True:
            print(bravo[alpha.index(name)])
    else:
        print("The persons name is not in the register.")

newclassification1(["Jacob", "Jane", "Jim"], ["Male", "Female", "Unknown"])

第二个：

def newclassification1(alpha,bravo):
    alpha = ["Jacob", "Jane", "Jim"]
    bravo = ["Male", "Female", "Unknown"]
    name = input("What is the persons name?")
    if name in alpha:
        while True:
            print(bravo[alpha.index(name)])
    else:
        print("The persons name is not in the register.")

newclassification1([], [])

Answer 3

def newclassification1(name):
    alpha = ["Jacob", "Jane", "Jim"]
    bravo = ["Male", "Female", "Unknown"]
    if name in alpha:
        print(bravo[alpha.index(name)])
    else:
        print("The persons name is not in the register.")

name = input("What is the persons name?")

newclassification1(name)

Answer 4

正如其他人所指出的，您应该修复缩进，并用您的 arguments 找出一些东西。 首先，当你在 function 中定义alpha和bravo时，每次调用它们都会被重写，我想你不希望发生这种情况。 其次，你应该修复缩进。 我建议有以下几点：

def newclassification1(alpha=["Jacob", "Jane", "Jim"],bravo=["Male", "Female", "Unknown"]):
        name = input("What is the persons name?")
        if name in alpha:
            print(bravo[alpha.index(name)])
        else:
            print("The persons name is not in the register.")

这样，默认情况下，您将使用您的alpha=["Jacob", "Jane", "Jim"]和bravo=["Male", "Female", "Unknown"]但以后可以轻松将其更改为您想要的任何内容当您致电 function 时。

此外，您不需要while True部分，因为它会在不停止执行的情况下运行

Answer 5

扩展 Celius 答案：

alpha = ["Jacob", "Jane", "Jim"]
bravo = ["Male", "Female", "Unknown"]
def newclassification1(alpha,bravo):
    name = input("What is the persons name?")
    print(bravo[alpha.index(name)] if (name in alpha) else "xxxxx")
newclassification1(alpha,bravo)

只需使用 Python 三元运算并将结果直接发送到打印语句