[英]How get two fields of different records in one record Mysql
我有一张包含此内容的表格(还有更多不相关的字段):
交易可以是购买或出售。 购买可以是id_factura 或者id_albaran,如果是购买id_factura,id_albaran 是Null,反之亦然,销售是一样的。 但是一次销售可以有两条具有相同 imei 的记录,正如我们在示例中看到的:id_purchasesale 2 和 3(在这种情况下,它总是具有相同的价格,例如 250)。
imei 字段只能作为一次购买(invoice_id 或 albaran_id)和一次或两次销售存在。
如果有购买但没有销售相同的imei,则无需出示。
表购买销售
id_purchasesale transaction id_factura id_albaran Model imei price
1 purchase 1 Null Samsung 30888 200
2 sale 1 Null Samsung 30888 250
3 sale Null 1 Samsung 30888 250
4 purchase Null 1 Apple 52101 300
5 sale 1 Null Apple 52101 380
6 purchase 2 Null Motorola 77520 300
7 sale 2 Null Motorola 77520 350
8 purchase 3 Null Xiaomi 29102 150
我想要获得的是以下结果,一个字段是购买价格,另一个字段是销售价格,另一个字段是这两个字段的利润和 model 字段。
imei price_purchase price_sale profit Model
30888 200 250 50 Samsung
52101 300 380 80 Apple
77520 300 350 50 Xiaomi
你可以试试下面 -
select imeid,
max(case when transaction='purchase' then price else 0 end) as purchase_price,
max(case when transaction='sale' then price else 0 end) as sale_price,
max(case when transaction='sale' then price else 0 end)-max(case when transaction='purchase' then price else 0 end) as profit,
model
from tablename
where transaction in ('purchase','sale')
group by imeid,model
having count(distinct transaction)=2
您应该使用同一个表 2,使用别名并按销售和购买过滤
select a.imei
, a.model
, a.price as price_purchase
, b.price as price_sale
, b.price - a.price as profit
from purchasesale a
inner join purchasesale b on a.imei = b.imei
and a.transaction ='purchase'
and b.transaction ='sale'
你的桌子设计一团糟。 如果您可以更改它,我会将这张表分成三个单独的表格,一张用于购买,一张用于销售,一张用于电话。
但是,在当前情况下,这应该满足您的要求:
SELECT
t1.imei as imei,
t1.price as price_purchase,
t2.price as price_sale,
(t2.price - t1.price) as profit,
t1.model as model
FROM purchasesale t1, purchasesale t2
WHERE t1.imei = t2.imei and
t1.transaction = 'purchase' and
t2.transaction = 'sale'
希望我有所帮助!
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