[英]How get two fields of different records in one record Mysql
我有一張包含此內容的表格(還有更多不相關的字段):
交易可以是購買或出售。 購買可以是id_factura 或者id_albaran,如果是購買id_factura,id_albaran 是Null,反之亦然,銷售是一樣的。 但是一次銷售可以有兩條具有相同 imei 的記錄,正如我們在示例中看到的:id_purchasesale 2 和 3(在這種情況下,它總是具有相同的價格,例如 250)。
imei 字段只能作為一次購買(invoice_id 或 albaran_id)和一次或兩次銷售存在。
如果有購買但沒有銷售相同的imei,則無需出示。
表購買銷售
id_purchasesale transaction id_factura id_albaran Model imei price
1 purchase 1 Null Samsung 30888 200
2 sale 1 Null Samsung 30888 250
3 sale Null 1 Samsung 30888 250
4 purchase Null 1 Apple 52101 300
5 sale 1 Null Apple 52101 380
6 purchase 2 Null Motorola 77520 300
7 sale 2 Null Motorola 77520 350
8 purchase 3 Null Xiaomi 29102 150
我想要獲得的是以下結果,一個字段是購買價格,另一個字段是銷售價格,另一個字段是這兩個字段的利潤和 model 字段。
imei price_purchase price_sale profit Model
30888 200 250 50 Samsung
52101 300 380 80 Apple
77520 300 350 50 Xiaomi
你可以試試下面 -
select imeid,
max(case when transaction='purchase' then price else 0 end) as purchase_price,
max(case when transaction='sale' then price else 0 end) as sale_price,
max(case when transaction='sale' then price else 0 end)-max(case when transaction='purchase' then price else 0 end) as profit,
model
from tablename
where transaction in ('purchase','sale')
group by imeid,model
having count(distinct transaction)=2
您應該使用同一個表 2,使用別名並按銷售和購買過濾
select a.imei
, a.model
, a.price as price_purchase
, b.price as price_sale
, b.price - a.price as profit
from purchasesale a
inner join purchasesale b on a.imei = b.imei
and a.transaction ='purchase'
and b.transaction ='sale'
你的桌子設計一團糟。 如果您可以更改它,我會將這張表分成三個單獨的表格,一張用於購買,一張用於銷售,一張用於電話。
但是,在當前情況下,這應該滿足您的要求:
SELECT
t1.imei as imei,
t1.price as price_purchase,
t2.price as price_sale,
(t2.price - t1.price) as profit,
t1.model as model
FROM purchasesale t1, purchasesale t2
WHERE t1.imei = t2.imei and
t1.transaction = 'purchase' and
t2.transaction = 'sale'
希望我有所幫助!
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