如何将多行值读入字典

Question

我有 file1 格式

field1-name, initial-val, desc
field2-name, initial-val, desc
field2-name, initial-val, desc
end-group1

field1-name, inital-val, desc
end-group2

......

我需要创建一个组字典，其中组作为键，字段列表作为值

group1: [(field1-name, initial-val, desc), (field2-name, inital-val, desc),(...)]
group2: [(field1-name, initial-val, desc)]

读取此文件并将其转换为组的最 Pythonic 方式是什么。 我有逐行读取和解析/存储值的代码，但想知道是否有更好的方法。

psedo-code
group = {}
with open(file, 'r') as f:
   for line in f:
      if line.startswith(r/end/):
          #extract group-name and create a tuple for field values
          group[group-name] = new_group
          new_group = []
          continue
      new_group.append(line)

Answer 1

考虑到您的文件格式是混合格式，逐行读取文件是最合适的解决方案，需要一个条件语句来确定是 append 到子列表还是创建新的 dict 条目：

group = {}
rows = []
with open(file, 'r') as f:
    for line in f:
        line = line.rstrip()
        if line.startswith('end-'):
            group[line.replace('end-', '', 1)] = rows
            rows = []
        elif line:
            rows.append(tuple(line.split(', ')))

group变为：

{'group1': [('field1-name', 'initial-val', 'desc'),
            ('field2-name', 'initial-val', 'desc'),
            ('field2-name', 'initial-val', 'desc')],
 'group2': [('field1-name', 'inital-val', 'desc')]}