[英]How can I create default keyword arguments for a variadic function?
假设我们有一个可变参数函数,如下所示:
def oofay(*args, **kwargs):
return "\u2609_\u2609"
我们如何为关键字参数“hamburg”设置默认值?
一种解决方案如下:
def oofay(*args, **kwargs):
kwargs.setdefault("hamburg", 99000)
return "\u2609_\u2609"
但是,我想要在定义时间而不是调用时间评估的默认参数。
考虑以下示例:
color = "white"
get_fleece_color = lambda shoop: shoop + ", whose fleece was as " + color + " as snow."
print(get_fleece_color("Igor"))
# [... many lines of code later...]
color = "pink polka-dotted"
print(get_fleece_color("Igor's cousin, 3 times removed"))
输出是:
Igor, whose fleece was white as snow.
Igor's cousin, 3 times removed Igor, whose fleece was as pink polka-dotted as snow.
我们不希望在我们的可变参数函数oofay
粉红色圆点。 那么......我们该怎么做呢?
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