[英]Is there a way to send a POST request to slack without using Webhook?
我尝试使用 webhook 将POST请求发送到我的松弛通道,但无济于事。
无论我做什么,它总是返回一个错误的请求。
有没有办法在不使用 webhook 的情况下向 slack 发送POST请求?
编辑:我正在使用的代码
import json
import urllib.request
#import botocore.requests as requests
def lambda_handler(event, context):
webhook=event['webhook']
#response = urllib.request.urlopen(message)
#print(response)
slack_URL = 'https://hooks.slack.com/services/mywebhookurl'
# req = urllib.request.Request(SLACK_URL, json.dumps(webhook).encode('utf-8'))
json=webhook
json=json.encode('utf-8')
headers={'Content-Type': 'application/json'}
#urllib.request.add_data(data)
req = urllib.request.Request(slack_URL, json, headers)
response = urllib.request.urlopen(req)
我认为当您在 utf-8 中编码utf-8
时会出现问题。 试试下面的脚本。
import json
import requests
# Generate your webhook url at https://my.slack.com/services/new/incoming-webhook/
webhook_url = "https://hooks.slack.com/services/YYYYYYYYY/XXXXXXXXXXX"
slack_data = {'text': "Hi Sarath Kaul"}
response = requests.post(webhook_url, data=json.dumps(slack_data),headers={'Content-Type': 'application/json'})
print response.status_code
如果你想使用urllib
import json
import urllib.request
import urllib.parse
url = 'https://hooks.slack.com/services/YYYYYYYYY/XXXXXXXXXXX'
data = json.dumps({'text': "Sarath Kaul"}).encode('utf-8') #data should be in bytes
headers = {'Content-Type': 'application/json'}
req = urllib.request.Request(url, data, headers)
resp = urllib.request.urlopen(req)
response = resp.read()
print(response)
在不使用任何额外的库(如请求)的情况下,仍然可以使用 urllib 内置的 python3 模块进行 GET/POST。 下面是示例代码:
def sendSlack(message):
req_param= {"From":"","Time":"","message":message}
slack_data = {
"blocks": [
{
"type": "header",
"text": {
"type": "plain_text",
"text": "Message",
}
},
{
"type": "section",
"fields": [
{
"type": "mrkdwn",
"text": "*From:*\n{}".format(req_param['From'])
},
{
"type": "mrkdwn",
"text": "*Time:*\n{}".format(req_param['Time'])
}
]
},
{
"type": "section",
"fields": [
{
"type": "mrkdwn",
"text": "*Message:*\n{}".format(req_param['message'])
}
]
}
]}
req = request.Request("https://hooks.slack.com/services/<COMPLETE THE URL>", data=json.dumps(slack_data).encode('utf-8')) # this will make the method "POST"
resp = request.urlopen(req)
print(resp.read())
确保在 slack 上发送正确的有效负载。 此代码对 AWS LAMBDA 也很有用。 请看下面的例子:
import json
from urllib import request
def sendSlack(message):
req_param= {"From":"","StartTime":"now","DialWhomNumber":message}
slack_data = {
"blocks": [
{
"type": "header",
"text": {
"type": "plain_text",
"text": "Message",
}
},
{
"type": "section",
"fields": [
{
"type": "mrkdwn",
"text": "*From:*\n{}".format(req_param['From'])
},
{
"type": "mrkdwn",
"text": "*Time:*\n{}".format(req_param['Time'])
}
]
},
{
"type": "section",
"fields": [
{
"type": "mrkdwn",
"text": "*Message:*\n{}".format(req_param['message'])
}
]
}
]}
req = request.Request("https://hooks.slack.com/services/<COMPLETE THE URL>", data=json.dumps(slack_data).encode('utf-8')) # this will make the method "POST"
resp = request.urlopen(req)
print(resp.read())
def lambda_handler(event, context):
# TODO implement
try:
print("-->GOT A REQUEST",event['queryStringParameters'])
sendSlack(event['queryStringParameters']['message'])
return {'body':json.dumps({'status':200,'event':'accepted'})}
except Exception as e:
print("Exception happenned",e)
return {
'statusCode': 400,
'body': json.dumps({'status':400,'event':'Something went wrong'})
}
import os
import json
from urllib2 import Request, urlopen, URLError, HTTPError
# environment variables
SLACK_WEBHOOK_URL = os.environ['SLACK_WEBHOOK_URL']
SLACK_CHANNEL = os.environ['SLACK_CHANNEL']
SLACK_USER = os.environ['SLACK_USER']
def lambda_handler(event, context):
# Read message posted on SNS Topic
message = json.loads(event['Records'][0]['Sns']['Message'])
# Construct a new slack message
slack_message = {
'channel': SLACK_CHANNEL,
'username': SLACK_USER,
'text': "%s" % (message)
}
# Post message on SLACK_WEBHOOK_URL
req = Request(SLACK_WEBHOOK_URL, json.dumps(slack_message))
try:
response = urlopen(req)
response.read()
print(slack_message['channel'])
except HTTPError as e:
print(e)
except URLError as e:
print(e)
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.