将文件拆分为列表后删除空格

Question

for line_1 in file_1 :
    split_op_1 = line_1.split(',')
    print(split_op_1)

输入： 547727, 547728, 553876, 557264,

输出： '547727', ' 547728', ' 553876', ' 557264',

所需输出： '547727', '547728', '553876', '557264',

如何从每个列表元素的开头删除多余的空间？

Answer 1

尝试：

split_op_1 = [i.strip() for i in split_op_1.split(',')]

Answer 2

尝试这个

for line_1 in file_1 :
    split_op_1 = line_1.split(',')
    print(list(map(str.strip, split_op_1)))

Answer 3

strip()函数在应用于字符串时删除前导和尾随空格：

https://docs.python.org/3/library/stdtypes.html#string-methods