[英]How to give an identifier for UIViewController (Swift) which has no storyboard?
我有多个以编程方式创建的视图控制器。 （没有故事板）
有没有办法给一个标识符或什么东西来区分视图控制器，就像给故事板一个标识符一样。
不，没有办法给一个标识符来区分视图控制器。 UIViewController 的名称是它的标识符。
如何快速使用代码移动到现有的UIViewController（在情节提要中）
[英]How to move to an existing UIViewController (in storyboard) with code in swift
是否可以通过 Swift/Objective-C 中的 UIViewController 或 Storyboard 以编程方式获取基本 UIViewController 的标识符？
[英]Is it possible to programmatically get the identifier of a basic UIViewController from an UIViewController or Storyboard in Swift/Objective-C?
iOS6：如何通过标识符在Storyboard中连接UIViewController？
[英]iOS6: How to connect UIViewController in Storyboard via Identifier?
SWRevealViewController with StoryBoard with storyboard Identifier in Swift 不继续如何做到这一点
[英]SWRevealViewController with StoryBoard with storyboard Identifier in Swift not segue how to do that
如何在不使用Swift中的Storyboard的情况下以编程方式加载UIViewController
[英]How to load a UIViewController programmatically without using Storyboard in Swift
在新的Storyboard中将值传递给UIViewController - Swift
[英]Passing Values to UIViewController in new Storyboard - Swift
Swift 中 UIViewController 的自定义初始化，在 storyboard 中设置接口
[英]Custom init for UIViewController in Swift with interface setup in storyboard
无法在 Swift Package 中显示 UIViewController 及其 Storyboard
[英]Not able to present UIViewController with its Storyboard in a Swift Package
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