我应该如何在我的 for 循环中添加 Try & except Block 来处理

Question

        # This is a guess the number game.
        import random

        print ('Hello, What is your name?')
        name = input()

        print('Well, ' + name + '! I am thinking of a number between 1 to 20.') 
        secretNumber = random.randint(1,20)
        print('Debug:' + str(secretNumber))

        for guessTaken in range (1,7):
            print('Take a guess. '+ name +'!' )
            guess =int(input())


            if guess<secretNumber:
                print('Your guess is too low')
            elif guess>secretNumber:
                print('Your guess is too high')
            else:
                break # This is for correct guess is equal.

        if guess ==secretNumber:
            print('Good Job, ' +name+ '! You guess my number in ' + str(guessTaken)+ ' guesses!')
        else:
            print('Nope, The number I was thinking of was ' +str(secretNumber))

嗨，我的超级程序员伙伴们，

所以我试图在这个程序中放置 Try 和 except 块，我尝试将它放在 guess=int(input()) 之后，不幸的是我无法让它工作。

所以我正在尝试处理 ValueError，所以假设用户需要输入整数（数字），如果他输入像“一”、“六”等字符串，程序就会崩溃。 我想处理这个案子。 请帮我一下。 :)

太感谢了。 眼镜蛇

Answer 1

这个怎么样，它重新询问用户是否输入了一个字符串：

        # This is a guess the number game.
        import random

        print ('Hello, What is your name?')
        name = input()

        print('Well, ' + name + '! I am thinking of a number between 1 to 20.') 
        secretNumber = random.randint(1,20)
        print('Debug:' + str(secretNumber))

        for guessTaken in range (1,7):
            print('Take a guess. '+ name +'!' )
            try:
               guess =int(input())
            except:
               print("Must be a number, try again: ")
               continue

            if guess<secretNumber:
                print('Your guess is too low')
            elif guess>secretNumber:
                print('Your guess is too high')
            else:
                break # This is for correct guess is equal.

        if guess ==secretNumber:
            print('Good Job, ' +name+ '! You guess my number in ' + str(guessTaken)+ ' guesses!')
        else:
            print('Nope, The number I was thinking of was ' +str(secretNumber))

Answer 2

如果用户输入的内容不是数字，python 将跳到异常，因为会发生错误，我在打印件中添加了一些文本以阐明游戏规则。 我在 for 循环之后使用了 else 有时对于用户无法在 7 次尝试中猜出数字的情况非常有用，您可以测试它并查看即使 else 不在 if 之后，当 if guess==secretNumber是真的，你打破了循环 else 语句没有做任何事情。 PS在这里回答还很陌生，所以请对我的回答提供反馈

import random

print ('Hello, What is your name?')
name = input()

print('Well, ' + name + '! I am thinking of a number between 1 to 20.') 
secretNumber = random.randint(1,20)
print('Debug:' + str(secretNumber))

for guessTaken in range (1,7):
    print('Take a guess. '+ name +'!, You Have 7 tries'  )
    try:
        guess = int(input())
        if guess<secretNumber :
            print('Your guess is too low')
        elif guess>secretNumber : 
            print('Your guess is too high')
        if guess == secretNumber:
            print('Good Job, ' + name + '! You guess my number in ' + str(guessTaken)+ ' guesses!')
            break # This is for correct guess is equal.
    except:
        print('Please Enter A number ' + name + 'and not anything else' )


else:
    print('Nope, The number I was thinking of was ' +str(secretNumber))