正则表达式：如何从此字符串中捕获多个文本？

Question

我有来自日志文件的文本，格式如下：

{s:9:\\\\"batch_num\\\\";s:16:\\\\"4578123645712459\\\\";s:9:\\\\"full_name\\\\";s:8:\\\\"John Doe\\\\"; s:6:\\\\"手机\\\\";s:12:\\\\"123456784512\\\\";s:7:\\\\"地址\\\\";s:5:\\\\"已编辑"\\\\";s :11:\\\\"create_time\\\\";s:19:\\\\"2017-09-10 12:45:01\\\\";s:6:\\\\"gender\\\\";s:1:\\\\ "1\\\\";s:9:\\\\"生日\\\\";s:10:\\\\"1996-03-09\\\\";s:11:\\\\"contact_num\\\\";s:1: \\\\"0\\\\";s:8:\\\\"身份\\\\";s:1:\\\\"2\\\\";s:6:\\\\"学校\\\\";N;s:14: \\\\"school_city_id\\\\";N;s:17:\\\\"profile_pic\\\\";s:43:\\\\"profile\\/2df0d9f29ab3ha65fed4847c8lb1o9sa.jpeg\\\\";s:14:\\\\"school_address\\\\" ;N;s:17:\\\\"enter_school_date\\\\";N;s:10:\\\\"专业\\\\";}

目前我只能使用正则表达式提取 batch_num ：

(?<=batch_num\\\\\\\\";s:16:\\\\\\\\")([0-9]{1,16})(?=\\\\\\\\)

链接： https : //regex101.com/r/OBaOY0/1/

题

我想从batch_num、full_name 和profile_pic 中提取值。 我的预期输出是：

4578123645712459

约翰·多伊

个人资料\\/2df0d9f29ab3ha65fed4847c8lb1o9sa.jpeg

如何使用正确的正则表达式获得所需的输出？

提前致谢。

Answer 1

通过将字符串转换为 json 来优雅地提取值的解决方案。

第一步：清洁绳子

import re, itertools
str_text = text.replace('\\','').replace(';','').replace('""','"').replace(':"','"').replace('N',',""')
str_text = re.sub('s:\d+',',', str_text)
str_text = re.sub('^{,','{', str_text)
str_text = re.sub('}$',':""}', str_text)
str_text = re.sub('(,)', lambda m, c=itertools.count(): m.group() if next(c) % 2 else ':', str_text)
str_text
#'{"batch_num":"4578123645712459","full_name":"John Doe","mobile":"123456784512","address":"Redacted","create_time":"2017-09-10 12:45:01","gender":"1","birthdate":"1996-03-09","contact_num":"0","identity":"2","school":"","school_city_id":"","profile_pic":"profile/2df0d9f29ab3ha65fed4847c8lb1o9sa.jpeg","school_address":"","enter_school_date":"","speciality":""}'

第 2 步：将字符串转换为 json 并提取

import json
str_json = json.loads(str_text)
print(str_json['batch_num'])
print(str_json['full_name'])
print(str_json['profile_pic'])
#4578123645712459
#John Doe
#profile/2df0d9f29ab3ha65fed4847c8lb1o9sa.jpeg

Answer 2

带有多个正则表达式。

批号

(?<="batch_num)\\\\{3}";s:\\d+:\\\\{3}"(\\d+)

全名

(?<="full_name)\\\\{3}";s:\\d+:\\\\{3}"(\\w+\\s\\w+)

全名（2个字以上）

(?<="full_name)\\\\{3}";s:\\d+:\\\\{3}"([\\w+\\s]{1,})

轮廓

(?<="profile_pic)\\\\{3}";s:\\d+:\\\\{3}"(\\w+\\\\{2}\\/\\w+\\.\\w+)

代码

regex_batch = r'(?<="batch_num)\\{3}";s:\d+:\\{3}"(\d+)'
regex_name = r'(?<="full_name)\\{3}";s:\d+:\\{3}"(\w+\s\w+)'
regex_prof = r'(?<="profile_pic)\\{3}";s:\d+:\\{3}"(\w+\\{2}\/\w+\.\w+)'

test_str = "{s:9:\\\\\\\"batch_num\\\\\\\";s:16:\\\\\\\"4578123645712459\\\\\\\";s:9:\\\\\\\"full_name\\\\\\\";s:8:\\\\\\\"John Doe\\\\\\\";s:6:\\\\\\\"mobile\\\\\\\";s:12:\\\\\\\"123456784512\\\\\\\";s:7:\\\\\\\"address\\\\\\\";s:5:\\\\\\\"Redacted\"\\\\\\\";s:11:\\\\\\\"create_time\\\\\\\";s:19:\\\\\\\"2017-09-10 12:45:01\\\\\\\";s:6:\\\\\\\"gender\\\\\\\";s:1:\\\\\\\"1\\\\\\\";s:9:\\\\\\\"birthdate\\\\\\\";s:10:\\\\\\\"1996-03-09\\\\\\\";s:11:\\\\\\\"contact_num\\\\\\\";s:1:\\\\\\\"0\\\\\\\";s:8:\\\\\\\"identity\\\\\\\";s:1:\\\\\\\"2\\\\\\\";s:6:\\\\\\\"school\\\\\\\";N;s:14:\\\\\\\"school_city_id\\\\\\\";N;s:17:\\\\\\\"profile_pic\\\\\\\";s:43:\\\\\\\"profile\\\\/2df0d9f29ab3ha65fed4847c8lb1o9sa.jpeg\\\\\\\";s:14:\\\\\\\"school_address\\\\\\\";N;s:17:\\\\\\\"enter_school_date\\\\\\\";N;s:10:\\\\\\\"speciality\\\\\\\";}"

m_batch = re.findall(regex_batch, test_str, re.MULTILINE)[0]
m_name = re.findall(regex_name, test_str, re.MULTILINE)[0]
m_prof = re.findall(regex_prof, test_str, re.MULTILINE)[0]
print(m_batch, m_name, m_prof)

输出

4578123645712459 John Doe profile\\\\/2df0d9f29ab3ha65fed4847c8lb1o9sa.jpeg

Answer 3

我想我有一个给你。 jpeg 匹配组 2 排除了两个 // 这就是为什么它们是粉红色的，它们是相同的匹配组：

https://regex101.com/r/OBaOY0/2

import itertools, re
a = '{s:9:\\"batch_num\\";s:16:\\"4578123645712459\\";s:9:\\"full_name\\";s:8:\\"John Doe\\";s:6:\\"mobile\\";s:12:\\"123456784512\\";s:7:\\"address\\";s:5:\\"Redacted"\\";s:11:\\"create_time\\";s:19:\\"2017-09-10 12:45:01\\";s:6:\\"gender\\";s:1:\\"1\\";s:9:\\"birthdate\\";s:10:\\"1996-03-09\\";s:11:\\"contact_num\\";s:1:\\"0\\";s:8:\\"identity\\";s:1:\\"2\\";s:6:\\"school\\";N;s:14:\\"school_city_id\\";N;s:17:\\"profile_pic\\";s:43:\\"profile\/2df0d9f29ab3ha65fed4847c8lb1o9sa.jpeg\\";s:14:\\"school_address\\";N;s:17:\\"enter_school_date\\";N;s:10:\\"speciality\\";}'.replace("\\","")

list(filter(None, list(itertools.chain.from_iterable(re.findall(r'(?:s:16:\")(\d+)|(?:s:8:\")(\w+ \w+)|(?:s:43:\")(\w+/\w+\.\w+)', a)))))

输出：

['4578123645712459',
 'John Doe',
 'profile/2df0d9f29ab3ha65fed4847c8lb1o9sa.jpeg']

Answer 4

您可以使用交替和捕获组获取示例数据的所有 3 个匹配项：

\b(?:batch_num|full_name|profile_pic)\b\\\\\\";s:\d+:\\\\\\"([^"]+)\\\\\\"

在零件中

• \\b(?:batch_num|full_name|profile_pic)\\b匹配单词边界之间的选项之一
• \\\\\\\\\\\\";s:\\d+:匹配\\\\\\"s:和 1+ 位数字
• \\\\\\\\\\\\"匹配\\\\\\"
• (捕获组 1
  • [^"]+匹配 1+ 次字符，除了"
• )关闭群组
• \\\\\\\\\\\\"匹配\\\\\\"

正则表达式演示| Python 演示

例如

import re

regex = r'\b(?:batch_num|full_name|profile_pic)\b\\\\\\";s:\d+:\\\\\\"([^"]+)\\\\\\"'
test_str = r'''{s:9:\\\"batch_num\\\";s:16:\\\"4578123645712459\\\";s:9:\\\"full_name\\\";s:8:\\\"John Doe\\\";s:6:\\\"mobile\\\";s:12:\\\"123456784512\\\";s:7:\\\"address\\\";s:5:\\\"Redacted"\\\";s:11:\\\"create_time\\\";s:19:\\\"2017-09-10 12:45:01\\\";s:6:\\\"gender\\\";s:1:\\\"1\\\";s:9:\\\"birthdate\\\";s:10:\\\"1996-03-09\\\";s:11:\\\"contact_num\\\";s:1:\\\"0\\\";s:8:\\\"identity\\\";s:1:\\\"2\\\";s:6:\\\"school\\\";N;s:14:\\\"school_city_id\\\";N;s:17:\\\"profile_pic\\\";s:43:\\\"profile\\/2df0d9f29ab3ha65fed4847c8lb1o9sa.jpeg\\\";s:14:\\\"school_address\\\";N;s:17:\\\"enter_school_date\\\";N;s:10:\\\"speciality\\\";}'''
matches = re.finditer(regex, test_str)
print(re.findall(regex, test_str))

输出

['4578123645712459', 'John Doe', 'profile\\\\/2df0d9f29ab3ha65fed4847c8lb1o9sa.jpeg']