[英]PHP Json file merge
我需要将 json 文件合并到 1 个文件中。
我在 3 个文件中有这样的 json
{
"count": 2077,
"records": [
{
"comm_date": "51529",
"Certificate_Number": "31",
},
{
"comm_date": "51529",
"Certificate_Number": "31",
}
]}
但问题是因为我有计数和记录数组在这里所以它没有成功合并
<?php
$a1 = file_get_contents ("EngroClaims.json");
$a2 = file_get_contents ("EngroClaims2.json");
$a6 = file_get_contents ("SCB1Claims.json");
$a7 = file_get_contents ("TotalParcoClaims.json");
$a8 = file_get_contents ("SAPTClaims.json");
$r = array_merge(json_decode($a1,true), json_decode($a2,true), json_decode($a6,true), json_decode($a7,true), json_decode($a8,true));
file_put_contents('conventional.json', json_encode($r));
?>
这是我的 php 代码,运行良好。 但我需要合并所有records
数组
例子
第一个文件
{
"count": 2,
"records": [
{
"comm_date": "1",
},
{
"comm_date": "2",
}
]}
第二个文件
{
"count": 3,
"records": [
{
"comm_date": "1",
},
{
"comm_date": "2",
},
{
"comm_date": "3",
}
]}
预期结果
{
"count": 9, //this count value is not imprtant assume it will show 1
"records": [
{
"comm_date": "1",
},
{
"comm_date": "2",
},
{
"comm_date": "1",
},
{
"comm_date": "2",
},
{
"comm_date": "3",
}
]}
你可以这样使用;
<?php
$a1 = file_get_contents ("EngroClaims.json");
$a2 = file_get_contents ("EngroClaims2.json");
$a1 = json_decode($a1, true);
$a2 = json_decode($a2, true);
$count = $a1["count"] + $a2["count"];
$data = array();
$data["count"] = $count;
foreach ($a1["records"] as $row) {
$data["records"][] = $row;
}
foreach ($a2["records"] as $row) {
$data["records"][] = $row;
}
echo json_encode($data);
我发现了你的问题。 去掉json中的逗号(代码中有说明)。
$a1 = '{
"count": 2077,
"records": [
{
"comm_date": "51529",
"Certificate_Number": "31", <--- THIS IS A PROBLEM
},
{
"comm_date": "51529",
"Certificate_Number": "31", <--- THIS IS A PROBLEM
}
]}';
/* in order for this solution to work you need to delete that comma.
Because there isn't a following data in the json so the comma should not be there */
检查此链接; http://sandbox.onlinephpfunctions.com/code/8dfab10352cf4966c95eb599d2ed8644b24b49ab
如果不需要计数,可以使用 array_merge_recursive
$r = array_merge_recursive(json_decode($a1,true), json_decode($a2,true),json_decode($a3,true));
echo json_encode($r);
会给你结果
{"count":[3,3,3],"records":[{"comm_date":"1"},{"comm_date":"2"},{"comm_date":"3"},{"comm_date":"1"},{"comm_date":"2"},{"comm_date":"3"},{"comm_date":"1"},{"comm_date":"2"},{"comm_date":"3"}]}
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