[英]PHP Json file merge
我需要將 json 文件合並到 1 個文件中。
我在 3 個文件中有這樣的 json
{
"count": 2077,
"records": [
{
"comm_date": "51529",
"Certificate_Number": "31",
},
{
"comm_date": "51529",
"Certificate_Number": "31",
}
]}
但問題是因為我有計數和記錄數組在這里所以它沒有成功合並
<?php
$a1 = file_get_contents ("EngroClaims.json");
$a2 = file_get_contents ("EngroClaims2.json");
$a6 = file_get_contents ("SCB1Claims.json");
$a7 = file_get_contents ("TotalParcoClaims.json");
$a8 = file_get_contents ("SAPTClaims.json");
$r = array_merge(json_decode($a1,true), json_decode($a2,true), json_decode($a6,true), json_decode($a7,true), json_decode($a8,true));
file_put_contents('conventional.json', json_encode($r));
?>
這是我的 php 代碼,運行良好。 但我需要合並所有records
數組
例子
第一個文件
{
"count": 2,
"records": [
{
"comm_date": "1",
},
{
"comm_date": "2",
}
]}
第二個文件
{
"count": 3,
"records": [
{
"comm_date": "1",
},
{
"comm_date": "2",
},
{
"comm_date": "3",
}
]}
預期結果
{
"count": 9, //this count value is not imprtant assume it will show 1
"records": [
{
"comm_date": "1",
},
{
"comm_date": "2",
},
{
"comm_date": "1",
},
{
"comm_date": "2",
},
{
"comm_date": "3",
}
]}
你可以這樣使用;
<?php
$a1 = file_get_contents ("EngroClaims.json");
$a2 = file_get_contents ("EngroClaims2.json");
$a1 = json_decode($a1, true);
$a2 = json_decode($a2, true);
$count = $a1["count"] + $a2["count"];
$data = array();
$data["count"] = $count;
foreach ($a1["records"] as $row) {
$data["records"][] = $row;
}
foreach ($a2["records"] as $row) {
$data["records"][] = $row;
}
echo json_encode($data);
我發現了你的問題。 去掉json中的逗號(代碼中有說明)。
$a1 = '{
"count": 2077,
"records": [
{
"comm_date": "51529",
"Certificate_Number": "31", <--- THIS IS A PROBLEM
},
{
"comm_date": "51529",
"Certificate_Number": "31", <--- THIS IS A PROBLEM
}
]}';
/* in order for this solution to work you need to delete that comma.
Because there isn't a following data in the json so the comma should not be there */
檢查此鏈接; http://sandbox.onlinephpfunctions.com/code/8dfab10352cf4966c95eb599d2ed8644b24b49ab
如果不需要計數,可以使用 array_merge_recursive
$r = array_merge_recursive(json_decode($a1,true), json_decode($a2,true),json_decode($a3,true));
echo json_encode($r);
會給你結果
{"count":[3,3,3],"records":[{"comm_date":"1"},{"comm_date":"2"},{"comm_date":"3"},{"comm_date":"1"},{"comm_date":"2"},{"comm_date":"3"},{"comm_date":"1"},{"comm_date":"2"},{"comm_date":"3"}]}
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