这是什么错误，因此我如何显示 .csv 文件中的前 5 个分数？

Question

我正在写一个骰子游戏，游戏结束后，两个玩家的名字都被保存到leaderboard2.csv文件中。 从leaderboard2.csv ，我试图显示前 5 名的分数。 这是怎么做的？

我看了很多教程，但它们都使用.txt文件，而我有一个.csv文件（在 Excel 中）用于排行榜。

我正在使用 python 3.3.4，我的代码就在下面：

import operator
with open("leaderboard2.csv", "r") as l:
    try:
        sort_key = operator.itemgetter(0)
        split_lines = (line.split(None, 1) for line in l) # splits the file into it's individual lines
        numeric_lines = ((int(line[0]), line[1]) for line in split_lines) # splits the numbers and the letters
        score = sorted(numeric_lines, key=sort_key, reverse=True) # sorts the numbers and letters into the opposite order
        leader_board1 = (score[0])
        leader_board2 = (score[1])
        leader_board3 = (score[2])
        leader_board4 = (score[3])
        leader_board5 = (score[4]) # gets the fifth line
    except IndexError:
        leader_board1 = '\n'
        leader_board2 = '\n'
        leader_board3 = '\n'
        leader_board4 = '\n'
        leader_board5 = '\n'
        print("--------- LEADER BOARD ---------")
        sys.stdout.write("FIRST PLACE: "), print(*leader_board1, sep=" points: ", end='')
        sys.stdout.write("SECOND PLACE: "), print(*leader_board2, sep=" points: ", end='\n')
        sys.stdout.write("THIRD PLACE: "), print(*leader_board3, sep=" points: ", end='')
        sys.stdout.write("FOURTH PLACE: "), print(*leader_board4, sep=" points: ", end='')
        sys.stdout.write("FIFTH PLACE: "), print(*leader_board5, sep=" points: ", end='')
        input(">>> ")

这是我收到的错误：

numeric_lines = ((int(line[0]), line[1]) for line in split_lines) # splits the numbers and the letters
ValueError: invalid literal for int() with base 10: 'ok,46'

对了， ok,46是.csv文件的第一行（ ok是用户名， 46是分数）

1）这个错误是什么意思，我该如何解决？

2) 我还能如何显示.csv文件中的前 5 个分数？

我的 cvs 文件如下所示：

k,32
no,75
test,33
example,65
a,10
l,50

提前致谢。

Answer 1

这是使用 Python 3.6+ 及其标准模块的解决方案：

import csv
from pathlib import Path
from collections import Counter

csvfile = Path('leaderboard2.csv')

with csvfile.open() as f:
    scores = Counter(dict(csv.reader(f)))

    # convert scores into integers
    # (there are better ways but I'm being didactic)
    for name in scores:
        scores[name] = int(scores[name])

    # list the top five
    for name, score in scores.most_common(5):
        print(f'{name}: {score}')

这是一个替代版本：

import csv
from pathlib import Path
from collections import Counter

csvfile = Path('leaderboard2.csv')

scores = Counter()

with csvfile.open() as f:
    for name,score in csv.reader(f):

    # convert score into integer
    score = int(score)
    scores[name] = score

# list the top five
for name, score in scores.most_common(5):
    print(f'{name}: {score}')

这是一个适用于早期版本的 Python 3 的版本：

import csv
from collections import Counter

scores = Counter()

with open('leaderboard2.csv') as f:
    for name,score in csv.reader(f):

    # convert score into integer
    score = int(score)
    scores[name] = score

# list the top five
for name, score in scores.most_common(5):
    print('%s: %s' % (name, score))

我希望它有助于作为起点。