Python 如何在一个 file.txt 中写入 5 行，在一个新的 file1.txt 中写入另外 3 行，例如 +=1

Question

我想要一个总共生成 12 行的脚本。 一个文件中的 5 行 Numbers.txt 第二个文件中的 5 行 Numbers0001.txt 第三个文件中的 2 行 Numbers0002.txt

有没有人以前处理过这个问题并且可以帮助我？

我的工作代码根据用户输入插入 5 行：

import random
import string

oneFile = open('‪Numbers.txt', 'w')
userInput = 0
key_count = 0
value_count = 0
chars = string.ascii_uppercase

for userInput in range(int(input('How many 12 digit keys do you want?'))):
    while key_count <= userInput:
        key_count += 1
        number = random.randint(1, 999)
        key = number

        text = str(''.join(random.sample(chars*6, 12)))
        oneFile.write(text + "\n")
oneFile.close()

这里是我在循环和 If Else 上挣扎的代码：

import random
import string


userInput = 0
key_count = 0
value_count = 0
chars = string.ascii_uppercase

if key_count > 5:
    for userInput in range(int(input('How many 8 digit keys do you want?'))):
        while key_count <= userInput:
                            oneFile = open(key_count('.txt', 'w'))
                            key_count += 1
                            number = random.randint(1, 999)
                            key = number
                            text = str(''.join(random.sample(chars*6, 8)))
                            oneFile.write(text + "\n")
                            oneFile.close()
else:
    oneFile = open('‪Numbers'+ +=1 +'.txt', 'w')
    oneFile.write(text + "\n") +5
    oneFile.close()

Answer 1

我不确定这是否是您要找的。 我只是拿了一个 12 项的列表（从 1 到 12 的整数）并将它们放入三个文件 Number.txt Numbers001.txt 和 Numbers002.txt

list_of_something = [1,2,3,4,5,6,7,8,9,10,11,12]

counter = 0
while counter < len(list_of_something):
    if counter < 5:

        oneFile = open("Numbers.txt", 'a')
        oneFile.write(str(list_of_something[counter]) + "\n")
        oneFile.close()
        counter +=1

    elif counter >=5 and counter < 10:
        oneFile = open("Numbers001.txt", 'a')
        oneFile.write(str(list_of_something[counter]) + "\n")
        oneFile.close()
        counter +=1

    else:
        oneFile = open("Numbers002.txt", 'a')
        oneFile.write(str(list_of_something[counter]) + "\n")
        oneFile.close()
        counter +=1

输出将是 3 个文件 - 第一个将有列表中的第 1-5 个第 6-10 个和第三个第 11-12 个项目

Answer 2

import random
import string


userInput = 0
key_count = 0
file_count = 0
value_count = 0
chars = string.ascii_uppercase

for userInput in range(int(input('How many 8 digit keys do you want?'))):
    while key_count <= userInput:

        if key_count % 5 == 0:
            file_count += 1
            oneFile = open('‪Numbers000'+ str(file_count) +'.txt', 'w')

        key_count += 1
        number = random.randint(1, 999)
        key = number

        text = str(''.join(random.sample(chars*6, 8)))
        oneFile.write(text + "\n")

        if key_count % 5 == 0:
                                    oneFile.close()