为什么我在 python 中的 len() 代码没有提供正确长度的字符串？

Question

我正在尝试使用 python 编写一个刽子手游戏，但在运行代码时无法获取正确长度的字符串以返回。 它会返回['clouds'] 10或['mango'] 9或['rose'] 8 ，而实际上它应该返回['clouds'] 6和['mango'] 5和['rose'] 4 .

请帮我看看我做错了什么！

这是我写的：

import random

word_list = ['tiger','dog','cake','disney','donut','rose','clouds','movies','sparkle','yoga','walrus','candle','mango','taco','flowers']

word = str(random.sample(word_list, 1))

word_len = len(word)

print(word, word_len)

Answer 1

random.sample(word_list, 1)返回单项list如 ["sparkle"] 并且您将其转换为str因此它在单词周围添加[""]因此单词变为'["sparkle"]'

我认为你需要：

import random

word_list = ['tiger','dog','cake','disney','donut','rose','clouds','movies','sparkle','yoga','walrus','candle','mango','taco','flowers']

word = random.sample(word_list, 1)
word_len = len(word[0])

print(word, word_len)

输出：

['sparkle'] 7

Answer 2

你使用了错误的方法

import random

word_list = ['tiger','dog','cake','disney','donut','rose','clouds','movies','sparkle','yoga','walrus','candle','mango','taco','flowers']
# return a k length list of unique elements chosen from the population sequence or set
# where k is 1, population sequence is word_list
print(random.sample(word_list, 1))

# to get random item from list you have to use random.choice
print(random.choice(word_list))