[英]SQL Statement to get Daily Totals across two days instead of Midnight
我最近写了一个查询来获取一个月内的每日总数。 查询工作得很好,但它从午夜到午夜。 我需要找到从早上 7:15 到第二天早上 7:15 的总数。 我们从 7:15 开始三班倒。
SELECT CONVERT(datetime,CAST(t_stamp AS DATE)), COUNT(bottles) AS 'Good Bottles'
FROM bottles
WHERE t_stamp
BETWEEN starrt
AND end
GROUP BY CAST(t_stamp AS DATE)
ORDER BY CAST(t_stamp AS DATE) ASC
只需减去一个偏移量。 一个简单的方法是:
SELECT CAST(DATEADD(minute, -(7 * 60 + 15), t_stamp) AS DATE),
COUNT(bottles) AS GoodBottles
FROM bottles
WHERE t_stamp BETWEEN starrt AND end
GROUP BY CAST(DATEADD(minute, -(7 * 60 + 15), t_stamp) AS DATE)
ORDER BY CAST(DATEADD(minute, -(7 * 60 + 15), t_stamp) AS DATE) ASC;
请注意, end
是一个非常糟糕的列名称,因为它是一个 SQL 关键字。
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