[英]In python, I'm trying to count each element in a list using a for loop, but it returns the element occurrence n many times
此函数多次返回元素出现次数:
def cold_compress():
l = int(input())
inp_list = []
num_list = []
for lines in range(l):
b = input()
inp_list.append(b)
print(b)
for item in inp_list:
for x in item:
print(item.count(x))
例如:如果我的输入是:
呜呜呜
33jjji
...它将输出:
3
3
3
4
4
4
4
2
2
3
3
3
1
我如何避免这种情况?
您可以使用Counter()来计算列表中的元素
示例代码:
from collections import Counter
listr = ["one","two","three","three","three","three",]
print(dict(Counter(listr)))
输出
{'one': 1, 'two': 1, 'three': 4}
在您的代码中实现 Counter():
from collections import Counter
def cold_compress():
listr = list(input())
print(dict(Counter(listr)))
cold_compress()
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