文件资源管理器在 Tkinter Python 程序中自动打开

Question

当我运行 python 程序时，文件资源管理器会自动打开。 我希望这仅在用户按下“打开”按钮时发生。

以上已经解决。

我目前在加密或解密文本方面遇到的问题是上传文件功能有效或类型字符串功能。 两者不在同一个程序中工作。

我将不胜感激任何帮助。

from tkinter import *
from tkinter import filedialog

class Caesar(Frame):
    LETTERS = "abcdefghijklmnopqrstuvwxyz"

    def UploadAction(self):
        filename = filedialog.askopenfilename(initialdir="/",
                                          title="Open File",
                                          filetypes=(("Text Files", "*.txt"), ("All Files", "*.*")))

        with open('caesartest.txt') as f:
        contents = f.read().splitlines()
        contents = ' '.join(map(str, contents))
        return contents

    def __init__(self, pencere):
        Frame.__init__(self, pencere)
        self.pencere = pencere

        Label(pencere, text="Enter your message: ", relief=GROOVE, width=20).place(x=20, y=30)
        self.Ent1 = Entry(pencere, width=30)
        self.Ent1.place(x=230, y=30)

        Label(pencere, text="Upload a .txt file: ", relief=GROOVE, width=20).place(x=20, y=80)
        Button(pencere, text="Open", relief=GROOVE, font="bold", command=self.UploadAction).place(x=230, y=80)
        self.Ent3 = Entry(pencere, width=24)
        self.Ent3.place(x=280, y=80)
        self.Ent3.insert(100, self.UploadAction())  

        Label(pencere, text="Enter key: ", relief=GROOVE, width=20).place(x=20, y=120)
        self.Ent2 = Entry(pencere, width=30)
        self.Ent2.place(x=230, y=120)

        Button(pencere, text="Encrypt", relief=GROOVE, font="bold", command=self.Encrypt).place(x=200, y=150)
        Button(pencere, text="Decrypt", relief=GROOVE, font="bold", command=self.Decrypt).place(x=280, y=150)

        Label(pencere, text="Result: ", relief=GROOVE, width=20).place(x=20, y=203)
        self.RESULT = Entry(pencere, width=30)
        self.RESULT.place(x=230, y=200)

    def Encrypt(self):
        key = int(self.Ent2.get())
        length = len(self.LETTERS)

        translation = ''

        text = self.Ent1.get()
        text = self.Ent3.get()
        text = re.sub('[^A-Za-z]+', '', text.lower())

        for character in text:
            if character in self.LETTERS:
                sayı = self.LETTERS.find(character)
                sayı = (sayı + key) % length
                translation += self.LETTERS[sayı]
            else:
                translation += character

        self.RESULT.delete(0, END)
        self.RESULT.insert(0, translation)

    def Decrypt(self):
        key = int(self.Ent2.get())
        length = len(self.LETTERS)

        translation = ''

        text = self.RESULT.get()
        text = re.sub('[^A-Za-z]+', '', text.lower())

        for character in text:
            if character in self.LETTERS:
                sayı = self.LETTERS.find(character)
                sayı = (sayı - key) % length
                translation += self.LETTERS[sayı]
            else:
                translation += character

        self.RESULT.delete(0, END)
        self.RESULT.insert(0, translation)

if __name__ == "__main__":
    root = Tk()
    root.title("Caesar")
    root.geometry("580x280+70+70")
    Caesar(root).pack(side="top", fill="both")
    root.mainloop()

Answer 1

至于我的问题是因为你使用

    self.Ent3.insert(100, self.UploadAction())   

在__init__因此它在开始时执行UploadAction() ，而不是在您按下按钮时。

您必须在由按钮执行的UploadAction()使用insert 。

def UploadAction(self):
    filename = filedialog.askopenfilename(initialdir="/",
                                      title="Open File",
                                      filetypes=(("Text Files", "*.txt"), ("All Files", "*.*")))

    if filename: 
        with open('caesartest.txt') as f:
            contents = f.read().splitlines()
            contents = ' '.join(map(str, contents))
        self.Ent3.insert(100, content) # <-- use it 

    # return contents # useless when used with `Button` 

def __init__(self, pencere):
    Frame.__init__(self, pencere)
    self.pencere = pencere

    Label(pencere, text="Enter your message: ", relief=GROOVE, width=20).place(x=20, y=30)
    self.Ent1 = Entry(pencere, width=30)
    self.Ent1.place(x=230, y=30)

    Label(pencere, text="Upload a .txt file: ", relief=GROOVE, width=20).place(x=20, y=80)
    Button(pencere, text="Open", relief=GROOVE, font="bold", command=self.UploadAction).place(x=230, y=80)
    self.Ent3 = Entry(pencere, width=24)

    self.Ent3.place(x=280, y=80) 

    # self.Ent3.insert(100, self.UploadAction()) # <-- don't do this