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[英]How can I pass a variable into a lambda function? Dynamic Lambda functions
[英]How could I store lambda functions inside a dictionary in python?
有人分享了他们的代码,我看到了一堆存储在我看来是字典中的函数。 所以,我喜欢这个想法并借用了它们。 那个人写的代码是用JS写的,我用的是Python,所以我把代码翻译成Python。
这是那个人用JS写的:
EasingFunctions = {
// no easing, no acceleration
linear: t => t,
// accelerating from zero velocity
easeInQuad: t => t * t,
// decelerating to zero velocity
easeOutQuad: t => t * (2 - t),
// acceleration until halfway, then deceleration
easeInOutQuad: t => t < .5 ? 2 * t * t : -1 + (4 - 2 * t) * t,
// accelerating from zero velocity
easeInCubic: t => t * t * t,
// decelerating to zero velocity
easeOutCubic: t => (--t) * t * t + 1,
// acceleration until halfway, then deceleration
easeInOutCubic: t => t < .5 ? 4 * t * t * t : (t - 1) * (2 * t - 2) * (2 * t - 2) + 1,
// accelerating from zero velocity
easeInQuart: t => t * t * t * t,
// decelerating to zero velocity
easeOutQuart: t => 1 - (--t) * t * t * t,
// acceleration until halfway, then deceleration
easeInOutQuart: t => t < .5 ? 8 * t * t * t * t : 1 - 8 * (--t) * t * t * t,
// accelerating from zero velocity
easeInQuint: t => t * t * t * t * t,
// decelerating to zero velocity
easeOutQuint: t => 1 + (--t) * t * t * t * t,
// acceleration until halfway, then deceleration
easeInOutQuint: t => t < .5 ? 16 * t * t * t * t * t : 1 + 16 * (--t) * t * t * t * t
}
如果您运行此代码,它就可以正常工作。 但是在我翻译的代码中,它给了我一个错误,说我错过了括号、逗号或冒号。 这是代码:
EasingFunctions = {
# no easing, no acceleration
linear: lambda t : t,
# accelerating from zero velocity
easeInQuad: lambda t : t ** 2,
# decelerating to zero velocity
easeOutQuad: lambda t : t * (2-t),
# acceleration until halfway, then deceleration
easeInOutQuad: (lambda t : t = (2*(t**2)) if t < 0.5 else ((-1+(4-2*t)) * t)),
# accelerating from zero velocity
easeInCubic: lambda t : t * t * t,
# decelerating to zero velocity
easeOutCubic: lambda t : (t-1) * t * t + 1,
# acceleration until halfway, then deceleration
easeInOutCubic: lambda t : t = 4*t*t*t if t < 0.5 else (t - 1) * (2 * t - 2) * (2 * t - 2) + 1,
# accelerating from zero velocity
easeInQuart: lambda t : t ** 4,
# decelerating to zero velocity
easeOutQuart: lambda t : 1 - (t-1) * t * t * t,
# acceleration until halfway, then deceleration
easeInOutQuart: lambda t : t = 8 * t * t * t * t if t < 0.5 else 1 - 8 * (t) * t * t * t
# accelerating from zero velocity
easeInQuint: lambda t : t ** 5,
# decelerating to zero velocity
easeOutQuint: lambda t : 1 + (t-1) * t * t * t * t,
# acceleration until halfway, then deceleration
easeInOutQuint: lambda t : t = 16 * t * t * t * t * t if t < 0.5 else 1 + 16 * (t-1) * t * t * t * t
}
令我困惑的是,错误被指示为第一个包含if
语句的键值。 我认为这在 Python 中是允许的,代码有什么问题?
正如您在评论中提到的,您仍然无法弄清楚如何使用字典的字符串键来做到这一点,我发布了这个答案。 尽管如此,在评论中部分提到了如何做到这一点。
a = {
'linear': lambda t: t,
'easeInQuad': lambda t: t ** 2,
'easeOutQuad': lambda t: t * (2-t),
'easeOutQuint': lambda t: 1 + (t - 1) * t * t * t * t,
}
print(a['linear'](69))
print(a['easeInQuad'](69))
print(a['easeOutQuad'](69))
print(a['easeOutQuint'](69))
结果:
69
4761
-4623
1541364229
同样,如评论中所述,Python 不支持--
操作。 希望这可以帮助。
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