如何在sql server中从csv格式的文本文件中获取表格的数据

Question

这是我从批量导入中获得的数据，我在名为 Drinks 的表中有：

| Descrip       |  10/02/20 07   |  17/02/20 08  |  24/02/20 09 |
| SL AGUA       |     NULL       |     NULL      |     2.861    |
| ALHAMBRA IPA  |     350        |     NULL      |     NULL     |
| Carlsberg     |     800        |     2.800     |     2.800    |
| CASIMIRO MH   |     NULL       |      55       |     NULL     |

我需要做一个查询来获取这样的数据：

| SL AGUA       |      20      |    09    |   2861   |
| ALHAMBRA IPA  |      20      |    07    |    350   |
| Carlsberg     |      20      |    07    |    800   |
| Carlsberg     |      20      |    08    |   2800   |
| Carlsberg     |      20      |    09    |   2800   |
| CASIMIRO MH   |      20      |    08    |     55   |

第一行有像标题（描述）这样的数据，但也有我需要的数据，比如日期和星期几。

可以做我需要的吗？ 谢谢。

Answer 1

将数据加载到临时表中，列来自第一行。

然后unpivot，我建议使用apply ：

select s.descrip, v.col1, vol2, v.val
from staging s cross apply
     (values ([10/02/20 07], 20, 7),
             ([10/02/20 08], 20, 8),
             ([10/02/20 09], 20, 9)
     ) v(val, col1, col2)
where v.val is not null;  -- or perhaps v.val <> ''

Answer 2

请按照以下步骤操作：

1. 表创建和插入数据

---

create table Drinks
(
    Head1 nvarchar(100),
    Head2 nvarchar(100),
    Head3 nvarchar(100),
    Head4 nvarchar(100)
)

insert into Drinks values('Descrip','10/02/20 07','17/02/20 08','24/02/20 09'),
                    ('SL AGUA',NULL,NULL,'2.861'),
                    ('ALHAMBRA IPA','350',NULL, NULL),
                    ('Carlsberg','800','2.800','2.800'),
                    ('CASIMIRO MH',NULL,'55',NULL)

2. 结果查询

---

;with tempCTE
as (
select head1,head2,head3,head4,
head5=(case when head2 is not null then head5 else '' end) ,
head6=(case when head3 is not null then head6 else '' end) ,
head7=(case when head4 is not null then head7 else '' end) 
from Drinks
cross apply (
    select  
    head5=right(Head2,2) + '|' + substring(Head2,7,2),
    head6=right(Head3,2)+'|'+substring(Head3,7,2),
    head7=right(Head4,2)+'|'+substring(Head4,7,2) 
     from Drinks
    where head1='Descrip'
) as tbl
cross apply (
        select 1 slno union select 2
) as tbl2
where head1<>'Descrip'

), resultCTE
 as
(
    select distinct head1,SplitHead1=left(head5,2),SplitHead2=right(head5,2),head2 from tempCTE where head2 is not null
    union
    select distinct head1,left(head6,2) ,right(head6,2),head3 from tempCTE where head3 is not null
    union
    select distinct head1,left(head7,2),right(head7,2),head4 from tempCTE where head4 is not null
)
select * from resultCTE

---

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